we assume the acceleration is constant. we choose the initial and final points 1.40s apart, bracketing the slowing-down process. then we have a straightforward problem about a particle under constant acceleration. the initial velocity is v xi =632mi/h=632mi/h( 1mi 1609m )( 3600s 1h )=282m/s (a) taking v xf =v xi +a x t with v xf =0 a x = t v xf −v xf = 1.40s 0−282m/s =−202m/s 2 this has a magnitude of approximately 20g (b) similarly x f −x i = 2 1 (v xi +v xf )t= 2 1 (282m/s+0)(1.40s)=198m
Answer:
0.037 N/m
Explanation:
The web acts as a spring, so it obeys Hook's law:
(1)
where
F is the force exerted on the web
k is the spring constant
x is the stretching/compression of the web
In this problem, we have:
- The mass of the fly is 
- The force exerted on the web is the weight of the fly, so:

- The stretching of the web is

So if we solve eq.(1) for k, we find the spring constant:

Answer:
11.56521 m/s
Explanation:
= Area of first section = 
= Area of second section = 
= Velocity in first section = 1.9 m/s
= Velocity in second section
From the continuity equation we get

The speed of the river through the section of rapids is 11.56521 m/s
The baseball would fall faster, because it has more mass