Answer:
The force parallel to the horizontal is 26.24 N
Explanation:
She pulls on the leash with a force F = 30 N, this force, since its at an angle of 29° (i will cal this angle 
), it has a force component on x (the horizontal, i will call this force 
) and a force component on y (the vertical, i will call this 
).
This can be seen in the attached picture.
Since we are asked about the force parallel to the horizontal, we need to find the component of the force , since is the adjacent angle, we need to use cosine:
since 
and 
The force parallel to the horizontal is 26.24 N
Answer:
The gravitational attraction of the Sun is what holds the planets in their elliptical orbits. So to explain this the mass effects the motion of the planets because the strength of gravitational force depends of the mass.
Explanation:
Answer:
Explanation:
Inital KE = (1/2) m v^2 = (1/2) * 1500 * 50^2 = 1,875,000 J
Final KE = (1/2) * 1500 * 100^2 = 7,500,000 J
But ,
4 * 1875000 = 7500000
so the KE has increased by 4 times.
Its vey True trust me on this when I say it is
This problem uses the relationships among current
I, current density
J, and drift speed
vd. We are given the total of electrons that pass through the wire in
t = 3s and the area
A, so we use the following equation to to find
vd, from
J and the known electron density
n,
so:
<span>The current
I is any motion of charge from one region to another, so this is given by:
</span>
The magnitude of the current density is:
Being:
<span>
Finally, for the drift velocity magnitude vd, we find:
</span>
Notice: The current I is very high for this wire. The given values of the variables are a little bit odd
