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3 years ago

Just need help with this one

Physics

1 answer:

GarryVolchara [31]3 years ago

7 0

Answer:

I have no clue

Explanation:

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A long solenoid that has 810 turns uniformly distributed over a length of 0.380 m produces a magnetic field of magnitude 1.00 10

IRINA_888 [86]

Answer:

0.037 A

Explanation:

Magnetic field = B = 1.00 e-4 T

Length = L = 0.380 m

Number of turns = 810

B = μ₀ N I / L

⇒ Current = I = B L / μ₀ N = ( 1 e-4) ( 0.380) / (4π × 10⁻⁷)(810)

= 0.037 A = 37.3 mA

5 0

3 years ago

A power company charges its customers for electricity based upon which one of the following?a. powerb. energyc. power per unit o

Vlad [161]

B. Energy

A power company charges its customers for electricity based upon B. Energy.

<h3>Explanation:</h3>

Kilo-watt Hours (kWh) is the unit that measures the electricity consumption of customers. Since Power is defined as the rate at which electrical energy is transferred by an electrical circuit per unit time,

$P = \frac{E}{t} \\E= P\times t$

If energy is transmitted at a constant rate over a period of time, the total energy in kilowatt hours is the product of power in kilowatts(kW) and time in hours (h)

$1\ kWh = 3.6\times 10^6\ Joules$

7 0

3 years ago

The greenhouse effect traps the sun's energy on Earth similar to

Gre4nikov [31]

D is the answer on this

5 0

3 years ago

How much voltage is in the primary coil if there are 3200 windings in the

Lesechka [4]

Answer:

Voltage in primary coil is 3.91 V

Explanation:

For transformer we know that the working principle is given as

$\frac{V_1}{V_2} = \frac{N_1}{N_2}$

here we know that

$V_1 [tex] = voltage in primary coil[tex]V_2 = 25 V$

$N_1 = 500$

$N_2 = 3200$

Now we have

$\frac{V_1}{25} = \frac{500}{3200}$

$V_1 = 3.91 V$

8 0

3 years ago

A world-class sprinter can burst out of the blocks to essentially top speed (of about 11.5 m/s) in the first 15.0 m of the race.

wolverine [178]

Given:
u = 0, initial speed (sprinter starts from rest)
v = 11.5 m/s, final speed
s = 15 m, distance traveled to attain final speed.

Let
a = average acceleration,
t = time taken to attain final speed.

Then
v² = u² + 2as
or
(11.5 m/s)² = 2*(a m/s²)*(15 m)
a = 11.5²/(2*15) = 4.408 m/s²

Also
v = u +a t
or
(11.5 m/s) = (4.408 m/s²)*(t s)
t = 11.5/4.408 = 2.609 s

Answer:
The average acceleration is 4.41 m/s² (nearest hundredth).
The time required is 2.61 s (nearest hundredth).

8 0

3 years ago