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KATRIN_1 [288]
3 years ago
15

Two objects are electrically charged. The net charge on one object is doubled. Therefore, the electric force _____.

Physics
2 answers:
creativ13 [48]3 years ago
7 0
If net charge on one object is doubled, then electric force will also get double. It is because they are directly proportional to each other.

Hope this helps!
labwork [276]3 years ago
3 0

Answer:

The electric force gets doubled.

Explanation:

According to Coulomb's law the force acting on charged bodies is directly proportional to the product of charges and inversely proportional to the square of distance between them.

Mathematically, it can be written as :

F=k\dfrac{q_1q_2}{r^2}

Where

r is the distance between the charges

In this question, it is given that the net charge on one object is doubled. As we can see from Coulomb's law, the electric force (F') gets doubled.

i.e. F'=2\times k\dfrac{q_1q_2}{r^2}

F' =2 F

Hence, this is the required solution.

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tamaranim1 [39]
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8 0
3 years ago
A boat race runs along a triangular course marked by buoys A, B, and C. The race starts with the boats headed west for 3700 mete
ale4655 [162]

Answer:

The  last two bearings are

49.50° and 104.02°

Explanation:

Applying the Law of cosine (refer to the figure attached):

we have

x² = y² + z² - 2yz × cosX

here,

x, y and z represents the lengths of sides opposite to the angels X,Y and Z.

Thus we have,

cos X=\frac{x^2-y^2-z^2}{-2yz}

or

cos X=\frac{y^2 + z^2-x^2}{2yz}

substituting the values in the equation we get,

cos X=\frac{2900^2 + 3700^2-1700^2}{2\times 2900\times 3700}

or

cos X=0.8951

or

X = 26.47°

similarly,

cos Y=\frac{1700^2 + 3700^2-2900^2}{2\times 1700\times 3700}

or

cos Y=0.649

or

Y = 49.50°

Consequently, the angel Z = 180° - 49.50 - 26.47 = 104.02°

The bearing of 2 last legs of race are angels Y and Z.

7 0
3 years ago
A 0.80 kg basketball traveling upward at 5.0 m/s impacts an 8.0 10 kg tennis ball traveling downward at 5.0 m/s. The basketball’
vlabodo [156]

To solve this problem we will apply the concepts related to the conservation of momentum. This can be defined as the product between the mass and the velocity of each object, and by conservation it will be understood that the amount of the initial momentum is equal to the amount of the final momentum. By the law of conservation of momentum,

m_1u_1+m_2u_2 = m_1v_1+m_2v_2

Here,

m_1 = Mass of Basketball

m_2 = Mass of Tennis ball

u_1 = Initial velocity of Basketball

u_2 = Initial Velocity of Tennis ball

v_1 = Final velocity of Basketball

v_2 = Final velocity of the tennis ball

Replacing,

(0.8)(0.5)+(0.1)(-5.0)=(0.8)(0.3)+(0.1)v_2

Solving for the final velocity of the tennis ball

v_2 = 11m/s^2

Therefore the velocity of the tennis ball after collision is 11 m/s

3 0
3 years ago
Read 2 more answers
Imagine that you drop an object of 10 kg, how much will be the acceleration and
Lelu [443]

If you do this on Earth, then the acceleration of the falling object is 9.8 m/s^2 ... NO MATTER what it's mass is.

If its mass is 10 kg, then the force pulling it down is 98.1 Newtons. Most people call that the object's "weight".

4 0
2 years ago
Find the final temperature of 375 grams of tea (c = 4.184 J/g°C) if its initial temperature is 95°C just before it is placed in
Minchanka [31]

Answer:

the final temperature of the tea is 7.39⁰C.

Explanation:

Given;

mass of the tea, m = 375 g

specific heat capacity of the tea, C = 4.184 JJ/g°C

initial temperature of the tea, t₁ = 95°C

the final temperature of the tea, t₂ = ?

Energy lost by the refrigerator, Q = 137,460 J

The energy lost by the refrigerator is given by the following formula;

-Q = mc(t₂ - t₁)

-137,460 =375 x 4.184(t₂ - 95°C)

-137,460 = 1569(t₂ - 95°C)

t_2-95 = \frac{-137,460}{1569} \\\\t_2-95 = -87.61\\\\t_2 = -87.61 + 95\\\\t_2 = 7.39 \ ^0 C

Therefore, the final temperature of the tea is 7.39⁰C.

4 0
3 years ago
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