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KATRIN_1 [288]
3 years ago
15

Two objects are electrically charged. The net charge on one object is doubled. Therefore, the electric force _____.

Physics
2 answers:
creativ13 [48]3 years ago
7 0
If net charge on one object is doubled, then electric force will also get double. It is because they are directly proportional to each other.

Hope this helps!
labwork [276]3 years ago
3 0

Answer:

The electric force gets doubled.

Explanation:

According to Coulomb's law the force acting on charged bodies is directly proportional to the product of charges and inversely proportional to the square of distance between them.

Mathematically, it can be written as :

F=k\dfrac{q_1q_2}{r^2}

Where

r is the distance between the charges

In this question, it is given that the net charge on one object is doubled. As we can see from Coulomb's law, the electric force (F') gets doubled.

i.e. F'=2\times k\dfrac{q_1q_2}{r^2}

F' =2 F

Hence, this is the required solution.

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A wave has a wavelength of 10 mm and a frequency of 14 hertz. What is its speed?
Katena32 [7]
0.14 meters per second .
3 0
3 years ago
Two remote control cars with masses of 1.16 kilograms and 1.98 kilograms travel toward each other at speeds of 8.64 meters per s
Black_prince [1.1K]

The initial momentum of the system can be expressed as,

p_i=m_1u_1+m_{2_{}}u_2

The final momentum of the system can be given as,

p_f=m_1v_1+m_{2_{}}v_2

According to conservation of momentum,

p_i=p_f

Plug in the known expressions,

\begin{gathered} m_1u_1+m_2u_2=m_1v_1+m_2v_2 \\ m_2v_2=m_1u_1+m_2u_2-m_1v_1 \\ v_2=\frac{m_1u_1+m_2u_2-m_1v_1}{m_2} \end{gathered}

Initially, the second mass move towards the first mass therefore the initial speed of second mass will be taken as negative and the recoil velocity of first mass is also taken as negative.

Plug in the known values,

\begin{gathered} v_2=\frac{(1.16\text{ kg)(8.64 m/s)+(1.98 kg)(-3.34 m/s)-(1.16 kg)(-2.16 m/s)}}{1.98\text{ kg}} \\ =\frac{10.02\text{ kgm/s-}6.61\text{ kgm/s+}2.51\text{ kgm/s}}{1.98\text{ kg}} \\ =\frac{5.92\text{ kgm/s}}{1.98\text{ kg}} \\ \approx2.99\text{ m/s} \end{gathered}

Thus, the final velocity of second mass is 2.99 m/s.

3 0
1 year ago
PLEASE ANSWER ASAP bbb
bazaltina [42]

Answer:

if one bulb burns out the other bulbs will also turn off because they are connected to each other.

8 0
3 years ago
A truck traveling at a velocity of 33m/s comes to a halt by decelerating at 11m/s^2. How far does the truck travel in the proces
snow_lady [41]

Answer:

<u><em>The truck was moving 16.5 m/s during the time it took to stop, which was 3 seconds. </em></u>

  • <u><em>Initial velocity = 33 m/s</em></u>
  • <u><em>Final velocity = 0 m/s</em></u>
  • <u><em>Average velocity = (33 + 0) / 2  m/s = 16.5 m/s</em></u>

Explanation:

  1. <u><em>First, how long does it take the truck to come to a complete stop?</em></u>
  1. <u><em>( 33 m/s ) / ( 11 m / s^2 ) = 3 seconds</em></u>
  1. <u><em>Then we can look at the average velocity between when the truck started decelerating and when it came to a complete stop. Because the deceleration is constant (always 11m/s^2) we can use this trick.</em></u>
4 0
3 years ago
By increasing the circuits resistance R, in a capacitive circuit the phase difference between the current in the circuit and pot
oksian1 [2.3K]

Answer:

B) Gets smaller

Explanation:

The difference of phase between current and voltage in a AC circuit is the phase  angle and it depends on the value of Z ( circuit impedance)

Z = R + X   where R is the resistive component and X the reactance component, which is due either to a presence of an  inductor or a capacitor. In any case the total impedance depends on R the resistive, and the phase angle φ is:  

tan⁻¹ φ =  X/R

Have a look to a pure capactive circuit (we are talking about AC current) in this case current leads voltage by 90⁰. If we add a resistor in the circuit  the current still will lead a voltage but in this condition the phase angle will be smaller,

If  R increase, X/R  decrease and tan⁻¹ φ also decrease

7 0
3 years ago
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