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LenKa [72]
3 years ago
5

More questions in the image.

Physics
1 answer:
Tamiku [17]3 years ago
8 0
True, they represent the direction of motion
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Use pythagorean's theorem for this, with 7 as a and 5 as b. pythagorean's theorem says that a^2 + b^2 = c^2, so 7^2 * 5^2 = c^2. this gives you 49 + 25 = c^2, so 74 = c^2. c = sqrt 74, which is approximately 8.60 km
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Convert the number from scientific into standard notation: 5.9 x 10-2
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Move the decimal point to:
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Why there is an atmosphere around earth while many planets dont have<br><br><br> PLZ ANSWER
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Answer:

Explanation:

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7 0
3 years ago
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Two pistons of a hydraulic lift have radii of 2. 67 cm and 20. 0 cm, respectively. The downward force on the 2. 67-cm piston tha
Makovka662 [10]

The downward force on the 2. 67-cm piston that is required to lift a mass of 2000 kg supported by the 20-cm piston is 350 N.

<h3>What is pascal law?</h3>

Pressure applied to a closed system of fluid will be transfer at each point of the fluid and the boundaries of the system.

Let suppose at the two point of such system the input force apllied is F₁ and output force we get is F₂. The area of this points is A₁ and A₂ respectively. As the pressure at both point is same. Then by the pascal law,

\dfrac{F_1}{A_1}=\dfrac{F_2}{A_2}\\

In case of radius,

\dfrac{F_1}{\pi r_1^2}=\dfrac{F_2}{\pi r_2^2}\\\\\dfrac{F_1}{r_1^2}=\dfrac{F_2}{ r_2^2}

Two pistons of a hydraulic lift have radii of 2. 67 cm and 20. 0 cm, respectively. Thus,

r_1=2.67\rm\; cm

r_2=20.0\rm\; cm

The downward force on the 2. 67-cm piston that is required to lift a mass of 2000 kg supported by the 20-cm piston is The force applied on second piston is,

F_2=mg\\F_2=2000\times9.81\\F_2=19620 \rm\; N

Put the values in the above formula,

\dfrac{F_1}{2.67^2}=\dfrac{19620}{20^2}\\F_1=\dfrac{19620\times2.67^2}{20^2}\\F_1\approx 350\rm\; N

Thus, the downward force on the 2. 67-cm piston that is required to lift a mass of 2000 kg supported by the 20-cm piston is 350 N.

Learn more about the pascal law here;

brainly.com/question/4262025

#SPJ4

4 0
2 years ago
The precision of a balance is ±0.02 g. The accepted value for a measurement is 26.86 g. Which measurement is in the accepted ran
Ivenika [448]
The range is: [26.86-0.02, 26.86+0.02] = [26.84, 26.88]
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3 years ago
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