Answer:
276g
Explanation:you are adding salt to water the mass is not destroyed so you just add the numbers hope this helps god bless
The higher the atomic number, the more shells an atom has. the electrons in the outer shell are more reactive as they have a weaker attraction to the nucleus as they are furthest away from the nucleus.
2[H⁺] + [O²⁻] → H₂O
Explanation:
Half reactions are usually composed of components of oxidation-reduction (redox) reaction where one element is losing electrons while another is gaining so they can come together into a compound. The half-reaction shows part of a reaction where the combining elements are charged and the product, from the redox, is neutral.
In this case, the H⁺ is carrying the positive charge because it is donating an electron to O²⁻, which is the reason the O²⁻ is carrying the negative charge. Note that we need 2 H⁺ for every one O²⁻. The O is being reduced while the H is being oxidized.
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The process that is being shown in the diagram below is Fertilization
Answer:
Amount of salt needed is around 2.3*10³ g
Explanation:
The salt content in sea water = 3.5 %
This implies that there is 3.5 g salt in 100 g sea water
Density of seawater = 1.03 g/ml
Volume of seawater = volume of tank = 62.5 L = 62500 ml
Therefore, the amount of seawater required is:
![=Density*Volume = 1.03g/ml*62500ml = 6.44*10^{4} g](https://tex.z-dn.net/?f=%3DDensity%2AVolume%20%3D%201.03g%2Fml%2A62500ml%20%3D%206.44%2A10%5E%7B4%7D%20g)
The amount of salt needed for the calculated amount of seawater is:
![=\frac{6.44*10^{4}g\ water*3.5g\ salt }{100g\ water} =2254 g =2.3*10^{3} g](https://tex.z-dn.net/?f=%3D%5Cfrac%7B6.44%2A10%5E%7B4%7Dg%5C%20water%2A3.5g%5C%20salt%20%7D%7B100g%5C%20water%7D%20%3D2254%20g%20%3D2.3%2A10%5E%7B3%7D%20g)