1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Stella [2.4K]
3 years ago
13

An unknown solution has a pH of 7. How would you classify this solution?

Chemistry
1 answer:
xenn [34]3 years ago
7 0
Solution with a ph of 7 Is neutral
You might be interested in
How come flowers usually contain more stamen the pistils
USPshnik [31]
<span>To make sure there are enough pollen to fertilize the seeds from the pistil. Not all pollen can make it to the pistil. It's the same as animals producing millions of sperms although only one is needed for fertilization.</span>
5 0
3 years ago
What volume of nitrogen gas is equal too 3.42x10^22 molecules of this substance
Bas_tet [7]

if i am correct the volume of nitrogen gas has to equal to molecules density, making the substance 1.27 liters :)

8 0
3 years ago
If a drop of blood is 0.05 mL, how many drops of blood are in the blood collection tube that holds 2 mL?
Irina18 [472]
40 drops of blood in a tube that holds 2 mL
5 0
3 years ago
Read 2 more answers
A sample of gas in a 14.6 L flexible container is at 25.0oC and 1.00atm. What is the volume of the sample when heated to 220.0oC
inn [45]

Answer: 24.1 L

Explanation:

To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1=14.6L\\T_1=25.0^oC=(25+273)K=298K\\V_2=?\\T_2=220.0^0C=(220+273)K=493K

Putting values in above equation, we get:

\frac{14.6}{298K}=\frac{V_2}{493}\\\\V_2=24.1L

Thus the volume of the sample when heated to 220.0oC and the pressure is constant is 24.1 L

7 0
3 years ago
The ph of a solution prepared by mixing 45.0 ml of 0.183 m koh and 35.0 ml of 0.145 m hcl is ________.
Naddika [18.5K]

Answer:

12.6.

Explanation:

  • We should calculate the no. of millimoles of KOH and HCl:

no. of millimoles of KOH = (MV)KOH = (0.183 M)(45.0 mL) = 8.235 mmol.

no. of millimoles of HCl = (MV)HCl = (0.145 M)(35.0 mL) = 5.075 mmol.

  • It is clear that the no. of millimoles of KOH is higher than that of HCl:

So,

[OH⁻] = [(no. of millimoles of KOH) - (no. of millimoles of HCl)] / (V total) = (8.235 mmol - 5.075 mmol) / (80.0 mL) = 0.395 M.

∵ pOH = -log[OH⁻]

∴ pOH = -log(0.395 M) = 1.4.

∵ pH + pOH = 14.

∴ pH = 14 - pOH = 14 - 1.4 = 12.6.

4 0
3 years ago
Other questions:
  • Chromium 6 is commonly referred to as?
    7·1 answer
  • \The specific heat of aluminum is 0.21 cal g°C . How much heat is released when a 10 gram piece of aluminum foil is taken out of
    11·1 answer
  • If I contain 3 moles of gas in a container with a volume of 60 liters and at a
    11·2 answers
  • A 7.11g sample of potassium chlorate was decomposed according to the following equation: 2KCLO3 --&gt;2KCL + 3O2 How many moles
    9·1 answer
  • A 10.50 gram sample of a compound is decomposed to yield 3.40 g Na, 2.37 g S, and 4.73 g O. What is the mass percentage of each
    12·1 answer
  • which one of the following statements about sodium chloride is incorrect a) within the crystal, each sodium ion is surrounded by
    12·1 answer
  • Which of the following ions would represent the ion of an element from group 2A
    15·1 answer
  • What is poly mineralic rock
    5·2 answers
  • calculate the amount of hydrogen sulphide that would be liberated by the action of sulphuric acid on 4.4 gram of ferrous sulphid
    14·1 answer
  • Which best describes the energy conversion that happens when windmills are
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!