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Marina CMI [18]
4 years ago
9

Use an addition or subtraction formula to find the exact value of the expression, as demonstrated in example 1. tan(105°)

Mathematics
1 answer:
strojnjashka [21]4 years ago
7 0
Use an addition or subtraction formula to find the exact value of the expression, as demonstrated in example 1. tan(105°)

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Find the height of triangle
Sophie [7]

Answer:

60

Step-by-step explanation:

First, divide 120 by two and get 60. Now do 120-60 to get 60. Set up proportion

60/x = x/60.

Cross multiply

x^2 = 3600

and now find the square root of 3600

60

8 0
3 years ago
According to an on-line dating website, 20% of the couples who are in committed relationships met on-line. Suppose you know 15 c
tester [92]
15/x = 20/100
15*100 = 20*x
1500 = 20x
1500/20 = 20x/20
75 = x

15/75 = 20/100

the expected number of couples who met online is 75
4 0
4 years ago
The ratio of boys to girls in Mrs. Ronilo's math class is 3 to 2. What percent of the class is boys?
maksim [4K]
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5 0
3 years ago
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What’s the domain for y=0.99x
alukav5142 [94]

Answer:

Solution: -∞ <x< ∞

Interval Notation: (-∞, ∞)

Step-by-step explanation:

7 0
3 years ago
The population of scores on a nationally standardized test forms a normal distribution with μ = 300 and σ = 50. If you take a ra
madreJ [45]

Answer:

P(\bar X

And using a calculator, excel or the normal standard table we have that:

P(Z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the scores of a population, and for this case we know the distribution for X is given by:

X \sim N(300,50)  

Where \mu=300 and \sigma=50

Since the distribution for X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

We can find the individual probability like this:

P(\bar X

And using a calculator, excel or the normal standard table we have that:

P(Z

4 0
3 years ago
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