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4 years ago

Use an addition or subtraction formula to find the exact value of the expression, as demonstrated in example 1. tan(105°)

Mathematics

1 answer:

strojnjashka [21]4 years ago

7 0

Use an addition or subtraction formula to find the exact value of the expression, as demonstrated in example 1. tan(105°)

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This is all-so hard.

seropon [69]

One

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3 years ago

Find all values of $x$ such that $\dfrac{x}{x+4} = -\dfrac{9}{x+3}$. If you find more than one value, then list your solutions i

mixer [17]

We start with

$\dfrac{x}{x+4} = -\dfrac{9}{x+3}$

Assuming that $x \notin \{-4,\ -3\}$ we can cross multiply the equation:

$x(x+3) = -9(x+4) \iff x^2+3x=-9x-36 \iff x^2+12x+36=0$

You can recognize the perfect square pattern in the quadratic equation:

$x^2+12x+36 = (x)^2 + 2\cdot x \cdot 6 + (6)^2 = (x+6)^2$

So, we have

$x^2+12x+36=0 \iff (x+6)^2 = 0 \iff x+6=0 \iff x=-6$

Which is the only solution, with multiplicity 2.

8 0

4 years ago

Read 2 more answers

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JulsSmile [24]

If you have a calculator click stat edit and put in the info

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3 years ago

Make a tree diagram for two coins that are tossed. Find the theoretical probability that at least one coin is heads. Express the

levacccp [35]

The answer is B

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8 0

3 years ago

A sample of 900 computer chips revealed that 75% of the chips do not fail in the first 1000 hours of their use. The company's pr

Vaselesa [24]

Answer:

No the evidence is not sufficient

Step-by-step explanation:

From the question we are told that

The sample size is $n = 900$

The sample proportion is $\r p = 0.75$

The population proportion is $p = 0.72$

The Null hypothesis is

$H_o : p = 0.72$

The Alternative hypothesis is

$H_a : p > 0.72$

The level of significance is given as $\alpha = 0.05$

The critical value for the level of significance is $t_{\alpha } = 1.645$

Now the test statistic is mathematically evaluated as

$t = \frac{\r p - p }{ \sqrt{\frac{p(1-p)}{\sqrt{n} } } }$

substituting values

$t = \frac{ 0.75 - 0.72 }{ \sqrt{\frac{0.72 (1-0.72)}{\sqrt{900} } } }$

$t = 0.366$

Since the critical value is greater than the test statistics then the Null hypothesis is rejected which there is no sufficient evidence to support the claim

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4 years ago