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jenyasd209 [6]
3 years ago
13

This circle is centered at the origin, and the length of its radius is 2. What iS

Mathematics
1 answer:
Igoryamba3 years ago
3 0

Answer:

Step-by-step explanation:

If the center of the circle is at the origin, the general formula for the circle is

x^2 + y^2 = r^2.

Since r  = 2 units in this particular problem, the equation of the circle is:

x^2 + y^2 = 2^2,  or  x^2 + y^2 = 4

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Find the value of the integral that converges.<br> ∫^-5_-[infinity] x^-2 dx.
Bingel [31]

Answer:

\int_{-\infty}^{-5} x^{-2}dx= \frac{1}{5} + \lim_{x\to -\infty} \frac{1}{x} =\frac{1}{5}

Because the \lim_{x\to -\infty} \frac{1}{x} =0

The integral converges to \frac{1}{5}

Step-by-step explanation:

For this case we want to find the following integral:

\int_{-\infty}^{-5} x^{-2}dx

And we can solve the integral on this way:

\int_{-\infty}^{-5} x^{-2}dx= \frac{x^{-2+1}}{-2+1} \Big|_{-\infty}^{-5}

\int_{-\infty}^{-5} x^{-2}dx= -\frac{1}{x} \Big|_{-\infty}^{-5}

And if we evaluate the integral using the fundamental theorem of calculus we got:

\int_{-\infty}^{-5} x^{-2}dx= \frac{1}{5} + \lim_{x\to -\infty} \frac{1}{x} =\frac{1}{5}

Because the \lim_{x\to -\infty} \frac{1}{x} =0

The integral converges to \frac{1}{5}

8 0
3 years ago
PRAGYA PLEASE HELP ME! (y-3)(y+4)?
Gemiola [76]

Answer:

y^2+y-12

Step-by-step explanation:

Once again, FOIL is the way to go!

First, Outside, Inside, Last

y^2+y-12

5 0
3 years ago
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icang [17]

Answer:

7d+2

Step-by-step explanation:

:)

6 0
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nikitadnepr [17]

Answer:

c,-0.45 ,

e. 1.16

g. 5/3

h. √2

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Step-by-step explanation:

Probability of any occurrence is always in the interval of 0 to 1. 0 and 1 inclusive.

0≤P(A)≤1

Any value outside this boundaries cannot be probability.

Therefore, -0.45,1.16,5/3 and √2 cannot be probability.

4 0
3 years ago
What happens to the graph of y = |x| when the equation changes to y |x-9|?
zhenek [66]
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