What is the image of (8,-1) after a reflection over the line y=x?

Solve the equation 2sin x cos x = cos x, for 0° < x≤ 90°

lilavasa [31]

Answer:

2sinx.Cosx=cosx

2sin90°.cos90°=cos90°

2×1.0=0

0=0

4 0

3 years ago

YALL PLEASE HELP IS IT ADDITION MULTIPLICATION OR SUB

alekssr [168]

Answer:

6 x $\frac{3}{4}$ = 4 $\frac{2}{4}$

Step-by-step explanation:

6 0

3 years ago

You are asked to do a study of shelters for abused and battered women to determine the necessary capacity in your city to provid

ohaa [14]

Answer:

Using the normal probability distribution, with a capacity of 350, it is enough for all abused on 90.82% of nights.

274 shelters will be needed.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 250, \sigma = 75$

If the city’s shelters have a capacity of 350, will that be enough places for abused women on 95% of all nights?

What is the percentile of 350?

This is the pvalue of Z when X = 350.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{250 - 150}{75}$

$Z = 1.33$

$Z = 1.33$ has a pvalue of 0.9082.

Using the normal probability distribution, with a capacity of 350, it is enough for all abused on 90.82% of nights.

If not, what number of shelter openings will be needed?

The 95th percentile, which is X when Z = 1.645. So

$Z = \frac{X - \mu}{\sigma}$

$1.645 = \frac{X - 150}{75}$

$X - 150 = 1.645*75$

$X = 274$

274 shelters will be needed.

5 0

3 years ago

Johanna used tiles to build a rectangler array with an array with an areavof 54.list all the possible dimensions of the array

lyudmila [28]

Assuming that all tiles must stay whole it would be:
1×54
2×27
3×18
6×9

4 0

3 years ago

Read the excerpt from Chapter 3 of Wheels of Change . In 1881, as women in the United States continued to struggle with hoops an

elena-s [515]

Step-by-step explanation:

Chapter 3 of Wheels of Change .

But the bicycle craze had a more lasting impact on women’s clothing than just the use of bloomers. Thanks in large part to cycling, the innovation of rational dress reformers were starting to take effect by the end of the 1890s. Corsets were on their way out, dresses were getting shorter, and women no longer wore the heavy, bulky undergarments that gave them round, unnatural shapes. These changes went a long way toward unburdening women and setting the stage for them to be healthier and more active in the coming century.

Based on the excerpt, women in the 1890s became more independent and their lives improved as a result of

a rise in the popularity of bicycles.

a rise in the popularity of corsets.

cycling becoming less socially acceptable.

clothing becoming more restrictive.

7 0

2 years ago