One way that double number lines are similar to finding equivalent ratios is that to find your answer on a double number line, you add equivalent ratios to your number line.
If you take a look at the graph carefully, you will see how the graph behaves from <em>right to left</em>.
I am joyous to assist you anytime.
The surface area is 1203cm good luck on your homeworek
Answer:
0 = a
Step-by-step explanation:
The first thing to do is subtract 5 from both sides.
a + 5 = 5a + 5
- 5 - 5
The 5's cancel out.
Now we have a + 0 = 5a
You next subtract the a from both sides.
a + 0 = 5a
-a -a
0 = 4a
Lastly would to get a by itself so then we divide 4 from both sides
0 = 4a
_ _
4 4
0 = a
Answer:
Step-by-step explanation:
Represent the length of one side of the base be s and the height by h. Then the volume of the box is V = s^2*h; this is to be maximized.
The constraints are as follows: 2s + h = 114 in. Solving for h, we get 114 - 2s = h.
Substituting 114 - 2s for h in the volume formula, we obtain:
V = s^2*(114 - 2s), or V = 114s^2 - 2s^3, or V = 2*(s^2)(57 - s)
This is to be maximized. To accomplish this, find the first derivative of this formula for V, set the result equal to 0 and solve for s:
dV
----- = 2[(s^2)(-1) + (57 - s)(2s)] = 0 = 2s^2(-1) + 114s - 2s^2
ds
Simplifying this, we get dV/ds = -4s^2 + 114s = 0. Then either s = 28.5 or s = 0.
Then the area of the base is 28.5^2 in^2 and the height is 114 - 2(28.5) = 57 in
and the volume is V = s^2(h) = 46,298.25 in^3
