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lana66690 [7]
3 years ago
13

A drawer of loose socks contains 2 red socks, 2 green socks, and 6 white socks. Which best describes how to determine the probab

ility of pulling out a white sock, not replacing it, and pulling out another white sock?
The probability that the first sock is white is (StartFraction 6 over 10 EndFraction) and that the second sock is white is (StartFraction 6 over 10 EndFraction), so the probability of choosing a pair of white socks is StartFraction 36 over 100 EndFraction = StartFraction 18 over 50 EndFraction.
The probability that the first sock is white is (StartFraction 1 over 10 EndFraction) and that the second sock is white is (StartFraction 1 over 10 EndFraction), so the probability of choosing a pair of white socks is StartFraction 1 over 100 EndFraction.
The probability that the first sock is white is (StartFraction 6 over 10 EndFraction) and that the second sock is white is (StartFraction 5 over 9 EndFraction), so the probability of choosing a pair of white socks is StartFraction 30 over 90 EndFraction = one-third.
The probability that the first sock is white is (StartFraction 1 over 10 EndFraction) and that the second sock is white is (StartFraction 1 over 9 EndFraction), so the probability of choosing a pair of white socks is StartFraction 1 over 90 EndFraction.
Mathematics
1 answer:
rosijanka [135]3 years ago
4 0

Answer: B

Step-by-step explanation: Took it on e 2020

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Answer:

Null hypothesis:\mu \leq 3.3  

Alternative hypothesis:\mu > 3.3  

z=\frac{3.4-3.3}{\frac{0.4}{\sqrt{50}}}=1.768  

Since is a one right tailed test the p value would be:  

p_v =P(z>1.768)=0.039  

Step-by-step explanation:

Data given and notation

\bar X=3.4 represent the sample mean  

\sigma=0.4 represent the population deviation for the sample

n=50 sample size  

\mu_o =3.3 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses to be tested  

We need to conduct a hypothesis in order to determine if the mean is higher than 3.3, the system of hypothesis would be:  

Null hypothesis:\mu \leq 3.3  

Alternative hypothesis:\mu > 3.3  

Compute the test statistic  

We know the population deviation, so for this case is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

We can replace in formula (1) the info given like this:  

z=\frac{3.4-3.3}{\frac{0.4}{\sqrt{50}}}=1.768  

P value

Since is a one right tailed test the p value would be:  

p_v =P(z>1.768)=0.039  

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