Answer:
60 student tickets and 40 adult tickets were sold
Step-by-step explanation:
Let s represent student tickets and a adult tickets, then the system of equations can be written as
s - a = 20 →(1)
2s + 4a = 280 → (2)
Multiply (1) by 4 and add to (2) to eliminate a
4s - 4a = 80 → (3)
Add (2) and (3) term by term
6s = 360 ( divide both sides by 6 )
s = 60
Substitute s = 60 into (1)
60 - a = 20 ( subtract 60 from both sides )
- a = - 40 ( multiply both sides by - 1 )
a = 40
Thus
60 student and 40 adult tickets were sold.
The lottery's anticipated worth is $80.
Given that,
The probability of receiving $125 is 0.25; the likelihood of receiving $100 is 0.3; and the likelihood of receiving $50 is 0.45.
A) EV=125*.2+100*.3+50*.5=$80
The lottery's anticipated worth is $80.
The expected value is obtained by multiplying each result by its likelihood.
The expected value of the lottery is then calculated by adding up all of these.
This is what we have: ;;
125(0.2) + 100(0.3) + 50(0.5) (0.5)
= 25 + 30 + 25 = $80
B) This is the formula for variance is shown in figure :
So, we can calculate the variance as follows:
.2*(125-80)^2+.3*(100-80)^2+.5*(50-80)^2=975
C) A risk-neutral person would pay $80 or less to play the lottery.
To learn more about probability click here:
brainly.com/question/14210034
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F(x) = x²-81
g(x) = (x-9) -1(x+9)
= (x-9) -x-9
g(x) • f(x)
= [x²-81 ] • [ (x-9) -x-9 ]
=[ x²-81 ] • [ (x-x -9-9) ]
= [ x²-81 ] •[0-18]
= [ x²-81] •[ -18]
= -18•x² +-81•-18
= -18x²+1458
the answer is 20.4 and I hope this helps!
4, 3, 2, 5, 6, 6, 10, 5, 6, 2, 3, 4, 6, 7, 14,5<br><br>
3. What is the mode(s) of the data set?
guapka [62]
Answer:
6
Step-by-step explanation:
6 shows up 4 times