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Lina20 [59]
3 years ago
14

Rank these ions according to ionic radius. Rb+ Sr2+ As3- Se2- Br-

Chemistry
1 answer:
Bond [772]3 years ago
6 0
Atomic radius increases going down and decreases left to right. Look at where these are located on the periodic table and apply this.
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HSiCl3+H2O=H10Si10O15+HCl
tiny-mole [99]

10 HSiCl3+ 15 H2O→H10Si10O15+ 30 HCl

Explanation:

Step 1: To make Si equal on both sides. put 10 in front of HSiCl3

10 HSiCl3+ H2O →H10Si10O15+ HCl

Step 2: By putting 30 in front of HCl, Cl can be balanced

10 HSiCl3+ H2O →H10Si10O15+ 30 HCl

Step 3: Now, balance O by putting 15 in front of H2O

10 HSiCl3+ 15 H2O→H10Si10O15+ 30 HCl

Hence the balanced equation is:

10 HSiCl3+ 15 H2O→H10Si10O15+ 30 HCl

5 0
4 years ago
Which element is probably most like Carbon? and why
Zolol [24]
Silicon because it is abundant on Earth. Also, carbon and silicon are both building blocks of life.
4 0
3 years ago
Read 2 more answers
4. Evaluate the information contained in this calculation and complete the
Neporo4naja [7]

Since you did not give a calculation, I will just give an example. Suppose that you are to burn 5 kg of methane (CH4) from 0 to 10°C. The specific heat capacity of methane is 4.475 kJ/kg-K.

H = mCpT

H = (5kg)( 4.475 kJ/kg-K)(10-0)

H = 223.75 kJ

Because the enthalpy is positive in value, methane takes in heat. 

7 0
4 years ago
"Which of the following processes takes place in the cytosol of a eukaryotic cell?" View Available Hint(s) Which of the followin
Rufina [12.5K]

Answer:

The correct answer is Glycolysis.

Explanation:

Glycolysis is a catabolic process that deals with the breakdown of glucose by 10 enzyme catalyzed steps to generate the end product pyruvate.

      Glycolysis take place in the cytosol of an eukaryotic cell because the concentration of glucose and enzymes that catalyzes the break down of glucose remain significantly high in the cytosol.

         

6 0
4 years ago
how do i caculate the trmperature change that 725 grams of aluminum will undergo when 2.35x10^4 Joules of thermal energy are add
sesenic [268]

Answer:

36°C

Explanation:

Given parameters:

Mass of aluminum = 725g

Quantity of heat  = 2.35 x 10⁴J

Unknown:

Temperature change  = ?

Solution:

To solve this problem, we simply use the expression below:

  The quantity of energy is given as:

          Q  = m C Δt

Q is the quantity of energy

m is the mass

C is the specific heat capacity of aluminum  = 0.9J/g°C

Δt is the change in temperature

  The unknown is Δt;

             Δt  = \frac{Q}{mc}    = \frac{2.35 x 10^{4} }{725 x 0.9}    = 36°C

4 0
3 years ago
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