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TEA [102]
3 years ago
14

Can someone help me out on this please <3 I have been stuck on this all day.​

Mathematics
1 answer:
ale4655 [162]3 years ago
8 0

I believe the answers to your question should be as follow:

-4, 3

4, 3

-4, -3

-8, 6

Please tell me if this isn't correct!

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How many solutions does this linear system have?<br> Y=2/3x+2<br> 6x-4y=-10
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2

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What are the intercepts of the function?
snow_tiger [21]

Answer:

x-int: (-1, 0), (-11, 0)

y-int: (0, 11)

Step-by-step explanation:

To find x-int, set equation equal to 0:

x² + 12x + 11

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7 0
4 years ago
What is the slope of a line perpendicular to the line whose equation is 3x-12y=2163x−12y=216.
Keith_Richards [23]

Answer:

Deleted account

Step-by-step explanation:

Here 3x-12y-216=0

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-12y= -3x + 216

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Please help! "Indicate the equation of the given line in standard form. The line containing the midpoints of the legs of right t
julsineya [31]

Nice. We're not really told which is the right angle. We can tell from the squared distances:


AB^2=(1 - -5)^2 + (1-5)^2=6^2+4^2=52


BC^2=(3-1)^2+(4-1)^2=2^2+3^2=13


AC^2=(3- -5)^2+(4 -5)^2=8^2+1^2=65


We see AC^2=AB^2+BC^2 so B is the right angle.


That was preliminary and probably indicated in an associated figure.


Now we want the line through the midpoint of the legs, AB and BC, in standard form.


The midpoint of AB is the average of the coordinates of A and B:


\left( \dfrac{-5 +1}{2}, \dfrac{5+1}{2} \right) = (-2,3)


The midpoint of BC is


\left( \dfrac{1 + 3}{2}, \dfrac{1 + 4}{2} \right) = ( 2, \frac 5 2)


The line through those points is


(y - 3)(2 - -2)=(x - -2)(\frac 5 2 - 3)


4y - 12 =  (x+2)(- \frac 1 2)


8y - 24 = -x -2


x + 8y = 22


That's the answer. Let's check it.


Midpoint of AB is (-2,3), -2 + 8(3)=22 good.


Midpoint of BC is (2,5/2), 2+8(5/2)=22 good.


\textrm{Answer: } x + 8y = 22


4 0
3 years ago
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