Answer:
------Br--
Explanation:
The steps involved in predicting the structure of the alkyl bromide compound are outlined below.
1) An examination of the product shows that the product could only be formed by a substitution reaction.
2) The structure of the alkyl bromide compound can be then predicted by replacing the methoxide group in the product after the substitution of bromine atom. This is because the methoxide ion acts as a strong nucleophile.
Therefore, by consideration the reaction mechanisms of reactions 1 and 2, it can be predicted that the structure of the alkyl bromide compound is ------Br--. A pictorial diagram of the alkyl bromide compound is also attached.
The answer to the question is 84
(Step By Step Explanation).
P1 V1/T1= P2 V2/T2
::0.75 x 120/295 = 1.25 x V2/345
90/295= 1.25V2/345
(cross multiply )
1.25V2 x 295 = 90 x 345
368.75V2 = 31050
(divide by the coefficient of the unknown) .
368.75V2/368.75 = 31050/368.75
V2 = 84.2. = 84
::The volume is 82.
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The balanced nuclear equations for the following:(b) Formation of francium-221 through α decay is (225,89)Ac -> (4,2)alpha + (221,87)Fr
<h3>
What is balanced nuclear equation?</h3>
A nuclear reaction is generally expressed by a nuclear equation, which has the general form, where T is the target nucleus, B is the bombarding particle, R is the residual product nucleus, and E is the ejected particle, and Ai and Zi (where I = 1, 2, 3, 4) are the mass number and atomic number, respectively. Finding a well balanced equation is critical for understanding nuclear reactions. Balanced nuclear equations provide excellent information about the energy released in nuclear reactions. Balancing the nuclear equation requires equating the total atomic number as well as the total mass number before and after the reaction using the rules of atomic number and mass number conservation in a nuclear reaction.
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The answer is X Ray
Hope it helps
Answer:
We will expect 4 moles of MgO to be formed (option b).
Explanation:
Step 1: The balanced equation
2Mg + O2 → 2MgO
Step 2: Data given
Number of moles of Magnesium = 4 moles
Oxygen = in excess → this means Magnesium is the limiting reactant
Magnesium will completely be consumed ( 4 moles). There will remain 0 moles.
For 2 moles of magnesium consumed, we need 1 mole of oxygen to produce 2 moles of MgO.
For 4 moles of magnesium, we need 4/2 = 2 moles of oxygen.
For 4 moles of magnesium, we will produce 4/1 = 4 moles of MgO
We will expect 4 moles of MgO to be formed (option b).