1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
givi [52]
3 years ago
9

If it requires 48.3 milliliters of 0.55 molar nitric acid to neutralize 15.0 milliliters of barium hydroxide, solve for the mola

rity of the barium hydroxide solution. Show all of the work used to solve this problem. Unbalanced equation: Ba(OH)2 + HNO3 yields Ba(NO3)2 + H2O
Chemistry
2 answers:
Gemiola [76]3 years ago
8 0
First you have to moles so multiply .0483L X .55M= .026565 Multiply moles by mole ratio which is 1/2, so the moles becomes .013283 now molarity=moles/volume; divide .013283/.015L=.885533M significant figures and you final answer is 0.89M
madam [21]3 years ago
4 0

<u>Answer:</u> The molarity of barium hydroxide solution is 0.8855 M.

<u>Explanation:</u>

The balanced chemical equation for the reaction is given as:

Ba(OH)_2+2HNO_3\rightarrow Ba(NO_3)_2+2H_2O

To calculate the molarity for a neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HNO_3

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is Ba(OH)_2

We are given:

n_1=1\\M_1=0.55M\\V_1=48.3mL\\n_2=2\\M_2=?M\\V_2=15mL

Putting values in above equation, we get:

1\times 0.55\times 48.3=2\times M_2\times 15\\\\M_2=0.8855M

Hence, the molarity of barium hydroxide solution is 0.8855 M.

You might be interested in
During beta-oxidation of fatty acids, ___________ is produced in peroxisomes but not in mitochondria. A) acetyl-CoA B) FADH 2 C)
stepan [7]

Answer:

The correct option is D

Explanation:

Normally, beta-oxidation of fatty acid occurs in the mitchondrial matrix, however, when the fatty acid chains are too long, the beta-oxidation occurs in the peroxisomes <u>where the oxidation is not attached to ATP synthesis but rather transferred (i.e high energy electrons are transferred) to O₂ to form hydrogen peroxide</u> (H₂O₂). This is the major difference between the beta-oxidation that occurs in the peroxisomes to that which occurs in the mitochondria.

4 0
3 years ago
A sample of marble has a volume of 6 cm3 and a density of 2.76 g/cm3. What is its mass?
zhuklara [117]

Answer:

16.56g

Explanation:

6*2.76=16.56...

6 0
3 years ago
Read 2 more answers
Post laboratory reflections 1 write equation [2] in the net ionic form 2. describe what happens when strong acid acts on limesto
oee [108]
It deteriorates. Definitely more than when you started.

4 0
3 years ago
A gas has a volume of 1.75L at -23°C and 150.0 kPa. At what temperature would the gas occupy 1.30L at 210.0 kPa?
Nastasia [14]

Answer:

At -13 ^{0}\textrm{C} , the gas would occupy 1.30L at 210.0 kPa.

Explanation:

Let's assume the gas behaves ideally.

As amount of gas remains constant in both state therefore in accordance with combined gas law for an ideal gas-

                                          \frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}

where P_{1} and P_{2} are initial and final pressure respectively.

           V_{1}  and V_{2} are initial and final volume respectively.

           T_{1} and T_{2} are initial and final temperature in kelvin scale respectively.

Here P_{1}=150.0kPa , V_{1}=1.75L , T_{1}=(273-23)K=250K, P_{2}=210.0kPa and V_{2}=1.30L

Hence    T_{2}=\frac{P_{2}V_{2}T_{1}}{P_{1}V_{1}}

            \Rightarrow T_{2}=\frac{(210.0kPa)\times (1.30L)\times (250K)}{(150.0kPa)\times (1.75L)}

            \Rightarrow T_{2}=260K

            \Rightarrow T_{2}=(260-273)^{0}\textrm{C}=-13^{0}\textrm{C}

So at -13 ^{0}\textrm{C} , the gas would occupy 1.30L at 210.0 kPa.

5 0
3 years ago
Determine the maximum number of moles of product that can be produced from 7.0 mol al and 8.0 mol cl2 according to the equation
Vilka [71]
The balanced chemical reaction is

<span>2al + 3cl2 = 2alcl3

To determine the maximum amount of product, we need to determine which is the limiting reactant. Then, use the initial amount of that reactant to calculate the amount of the product that would be produced. We do as follows:

7 mol Al (3 mol Cl2 / 2 mol Al) = 10.5 mol Cl2
8 mol Cl2 ( 2 mol Al / 3 mol Cl2) = 5.3 mol Al
Thus, it is Cl2 that is the limiting reactant.

8 mol Cl2 ( 2 mol AlCl3 / 3 mol Cl2) = 5.3 moles of AlCl3 is produced</span>
5 0
4 years ago
Other questions:
  • A volume of 80.0 mL of aqueous potassium hydroxide (KOH) is titrated against a standard solution of sulfuric acid (H2SO4). What
    13·1 answer
  • Classify blood as a mixture or a pure substance. if blood is a mixture, classify it as either heterogeneous or homogeneous. if b
    6·1 answer
  • Why can polar water molecules pass through a cell membrane?
    12·1 answer
  • 2. A block of aluminum with a mass of 140g is cooled from 98.4oC to 62.2oC with a release of 1137J of heat. From these data, cal
    11·1 answer
  • When did the largest difference in high tide occur on the same day?
    11·1 answer
  • Devon noticed that it has rained more this year than it did in each of the previous 10 years. How might this increase in rainfal
    11·1 answer
  • Which human activity would most likely decrease the amount of carbon in the atmosphere?
    8·2 answers
  • The time necessary for the decay of one- half sample of a radioactive substance is a _____. mass defect daughter half life nucli
    11·2 answers
  • write the balanced reaction for the complete combustion of C11(subscript) H24 by diatomic O2. show all work
    7·1 answer
  • How does the conflict in this passage develop a theme?
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!