Answer:
1. protons
2. hydrogen
3. protons plus neutrons
4. nuclear force
5. they are composite particles
6. proton-positive-inside nucleus; neutron-no charge-inside nucleus; electron-negative-outside nucleus/electron cloud
7. sublevels
8. 4 energy levels
Explanation:
Here are the steps for finding an emprical formula.
To begin, we need to change the grams to a percentage. We can simply take the number and call it our percentage. (i.e 0.262%)
Then, we have a simply stoichiometry step. We put our starting number over 1, as usual. The next "Step" is putting in the molar mass of that particular element on the bottom, with one on top. It should look like this:
0.262% N 1
-------------- x ----------------
1 14.007g N
We would then divide those two numbers to get our answer. Repeat for the other elements included, until we have all of them done.
After that, we need to find the smallest number that was the answer to one of the equations. For example, if the product of Hydrogen was the smallest formed, we would locate that number. We then divide ALL of our answers by that smallest number.
Remember, whenever doing empirical formulas, significant figures matter.
Once we have our smallest numbers, we need to round our numbers to the nearest whole number. HOWEVER, to do this we need to multiply all of the numbers by the SAME whole number.
For example, if one of our numbers was 1.33, we would multiply by 3 to get a whole number. However, we would also need to multiply the rest of our products by the same number. If we do not get close to whole numbers (you can round), we need to try with multiplying a different number.
Then, we need to take those whole numbers we got for each number, and plug in to make a compound. For example, if our products were 6 for nitrogen, 3 for hydrogen, and 2 for chlorine, our final empirical formula would be N6H3Cl2.
Hope I could help! If it was a bit wordy please let me know and I'd be more than willing to clarify.
Answer:
Na3PO4 is excess reactant, CaCl2 is limiting reactant.
Explanation:
3CaCl2 + 2Na3PO4 ---> Ca3(PO4)2 + 6NaCl
from reaction : 3 mol 2 mol
given: 6 mol 5 mol (X)
X = (6*2)/3 = 4 mol Na3PO4
For 6 mol CaCl2 we need 4 mol Na3PO4, but we have 5 mol Na3PO4,
Na3PO4 is excess reactant, so CaCl2 is limiting reactant.
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