Answer:
259 mg is the mass of silver chloride required to plate 195 mg of pure silver.
Explanation:
Silver chloride contains 75.27 percent silver. It can be concluded that:-
For every 100 mg of silver chloride, 75.27 mg of silver we can get.
So, to produce 195 mg of silver, the amount of silver chloride required can be calculated as:-
<u>259 mg is the mass of silver chloride required to plate 195 mg of pure silver.</u>
Answer: 
concentration of 
= 0.50 M
concentration of 
= 0.25 M
Explanation:
The dissociation equation of 
is:
According to stoichiometry:
1 mole of gives 2 moles of
Thus 0.25 moles of gives =
moles of
Similarly,
1 mole of gives = 1 mole of
Thus 0.25 moles of gives =
moles of
Thus the concentration of and are 0.50 M and 0.25 M respectively.
Hydrogen bonding, a particularly strong dipole-dipole force, causes a powerful attraction between water molecules, which results in a high boiling point.
count the elements in eqn MgI2 + Br2 -> MgBr2 + I2
1 Mg, 2I, 2Br on the left n
1 Mg, 2I, 2Br on the right
they are equal so the eqn is balanced
