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VladimirAG [237]
3 years ago
14

Light travels extremely rapidly (c = 3.00×108 m/s ). Suppose you had to travel 40 miles to work every day. If you traveled at th

e speed of light for the entire trip, how long would it take you to get to work (in seconds)? [1 mile = 1.61 km]
Chemistry
1 answer:
Reptile [31]3 years ago
7 0
Given , Speed of light = 3 × 10⁸ m/s 
             Distance = 40 × 1.61× 1000 m 
                           = 264400 m
 We know that, speed = distance/time 
                   so, time = distance/speed
                             t = 264400 / 3 × 10⁸
                             t = 0.00881333 sec  Approx
The answer is 0.00881333 sec  Approx
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When the pressure that a gas exerts
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Answer:

The pressure changes from 2.13 atm to 1.80 atm.

Explanation:

Given data:

Initial pressure = ?

Final pressure = 1.80 atm

Initial temperature = 86.0°C (86.0 + 273 = 359 K)

Final temperature = 30.0°C (30+273 =303 K)

Solution:

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

P₁ = P₂T₁ /T₂

P₁ = 1.80 atm × 359 K / 303 K

P₁ = 646.2 atm. K /303 K

P₁ = 2.13 atm

The pressure changes from 2.13 atm to 1.80 atm.

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Determine the enthalpy for this reaction: Al(OH)3(s)+3HCl(g)→AlCl3(s)+3H2O(l)
ivanzaharov [21]
<span>Important information to solve the exercise :
Substance ΔHf (kJ/mol):
HCl(g)= −92.0 </span><span>kJ/mol
Al(OH)3(s)= −1277.0 </span><span><span>kJ/mol
</span> H2O(l)= −285.8 </span><span>kJ/mol
AlCl3(s) =−705.6 </span><span>kJ/mol

</span><span>Al(OH)3(s)+3HCl(g)→AlCl3(s)+3H2O(l)
    reactants                         products

products- reactants:</span><span>

(−705.6) + (3 x −285.8) - ( −1277.0 ) - (3 x −92.0 ) = - 10.0 </span>kJ per mole at 25°C
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6 0
3 years ago
5) Calculate the molality of 0.210 mol of KBr dissolved in 0.075kg pure<br> water?
Margaret [11]

Answer:

\boxed {\boxed {\sf 2.8 \ m }}

Explanation:

The formula for molality is:

m=\frac{moles \ of \ solute}{kg \ of \ solvent}

There are 0.210 moles of KBr and 0.075 kilograms of pure water.

moles= 0.210 \ mol \\kilograms = 0.075 \ kg

Substitute the values into the formula.

m= \frac{ 0.210 \ mol }{0.075 \ kg}

Divide.

m= 2.8 \ mol/kg= 2.8 \ m

The molality is <u>2.8 moles per kilogram</u>

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Explanation:

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