Formula: NA2S2O3. Valency: 2
Answer
The empirical formula is CrO₂Cl₂
Explanation:
Empirical formula is the simplest whole number ratio of an atom present in a compound.
The compound contain, Chromium=33.6%
Chlorine=45.8%
Oxygen=20.6%
And the molar mass of Chromium(Cr)=51.996 g mol.
Chlorine containing molar mass (Cl)= 35.45 g mol.
Oxygen containing molar mass (O)=15.999 g mol.
Step-1
Then,we will get,
Cr=
mol
Cl=
mol.
O=
mol.
Step-2
Divide the mole value with the smallest number of mole, we will get,
Cr=
![\frac{0.64}{0.64} =1](https://tex.z-dn.net/?f=%5Cfrac%7B0.64%7D%7B0.64%7D%20%3D1)
Cl=
![\frac{1.29}{0.64} =2](https://tex.z-dn.net/?f=%5Cfrac%7B1.29%7D%7B0.64%7D%20%3D2)
O=
![\frac{1.28}{0.64} =2](https://tex.z-dn.net/?f=%5Cfrac%7B1.28%7D%7B0.64%7D%20%3D2)
Then, the empirical formula of the compound is CrO₂Cl₂ (Chromyl chloride)
Explanation:
Upon dissolution of KCl heat is generated and temperature of the solution raises.
Therefore, heat generated by dissolving 0.25 moles of KCl will be as follows.
![17.24 kJ/mol \times 0.25 mol](https://tex.z-dn.net/?f=17.24%20kJ%2Fmol%20%5Ctimes%200.25%20mol)
= 4.31 kJ
or, = 4310 J (as 1 kJ = 1000 J)
Mass of solution will be the sum of mass of water and mass of KCl.
Mass of Solution = mass of water + (no. of moles of KCl × molar mass)
= 200 g + ![(0.25 mol \times 54.5 g/mol)](https://tex.z-dn.net/?f=%280.25%20mol%20%5Ctimes%2054.5%20g%2Fmol%29)
= 200 g + 13.625 g
= 213.625 g
Relation between heat, mass and change in temperature is as follows.
Q = ![mC \Delta T](https://tex.z-dn.net/?f=mC%20%5CDelta%20T)
where, C = specific heat of water = ![4.184 J/g^{o}C](https://tex.z-dn.net/?f=4.184%20J%2Fg%5E%7Bo%7DC)
Therefore, putting the given values into the above formula as follows.
Q = ![mC \Delta T](https://tex.z-dn.net/?f=mC%20%5CDelta%20T)
4310 J =
Thus, we can conclude that rise in temperature will be
.
Answer:
Explanation:
Function. The mitochondrion is the site of ATP synthesis for the cell. The number of mitochondria found in a cell are therefore a good indicator of the cell's rate of metabolic activity; cells which are very metabolically active, such as hepatocytes, will have many mitochondria.