Your notation is wrong. You cannot have big H and little h at the same time. You need to find h(-3) or H(-3).
I assume you need h(-3), which means that the function is h(x) = 4x - 7.
See picture.
This one is actually easy!!!
So you only have a 5 foot long board and you want to cut it into 6 equal pieces the only thing you can do is divide.
It is not A Because that it is making more.
It is not B because that is ubtracting and it would not be equal.
It would not be C it is the incorrect steps.
It is D because your supposed to do 5 divided by 6 to make it equal pieces 5 divided by 6 = .83. and 6 x .83 = 4.9999 which is 5.
Answer is D give me brainliest
The y-intercept of a function is that function's value when x=0.
.. f(0) = 4
.. g(0) = 0
These y-intercepts differ by 4.
If you want them to differ by zero (be the same), you have to move them to the same point.
Selection 1. Moves f(0) down 3 (to 1) and g(0) up 1 (to 1), so moves the y-intercepts to the same point. This is what you want, so this is an appropriate answer selection.
Selection 2. Moves f(0) up 4 (to 8) and g(0) down 1 (to -1). 8 and -1 are not the same point, so this is not the answer.
Selection 3. Moves f(0) down 2 (to 2) and g(0) up 1 (to 1). 2 and 1 are not the same point, so this is not the answer.
Selection 4. Moves f(0) up 3 (to 7) and g(0) down 6 (to -6). 7 and -6 are not the same point, so this is not the answer.
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The appropriate choice is the 1st one.
f(x) - 3 and
g(x) + 1
Answer:
ABOVE the x-axis
Step-by-step explanation:
Please use "^" to denote exponentiation: y = x^2 + 2x + 3
To find the vertex, we must complete the square of y = x^2 + 2x + 3, so that we have an equivalent equation in the form f(x) = (x - h)^2 + k.
Starting with y = x^2 + 2x + 3,
we identify the coefficient of x (which is 2), take half of that (which gives
us 1), add 1 and then subtract 1, between "2x" and "3":
y = x^2 + 2x + 1 - 1 + 3
Now rewrite x^2 + 2x + 1 as (x + 1)^2:
y = (x + 1)^2 - 1 + 3, or y = (x + 1)^2 + 2. Comparing this to f(x) = (x - h)^2 + k, we see that h = 1 and k = 2. This tells us that the vertex of this parabola is at (h, k): (1, 2), which is ABOVE the x-axis.