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romanna [79]
3 years ago
13

A sample of carbon- 12 has a mass of 6.00 g. How many moles of carbon are in the sample?

Chemistry
1 answer:
marin [14]3 years ago
5 0

Answer:

0.5 moles

Explanation:

to get the number of moles, you have to divide the mass by molar mass.

the molar mass of carbon-12 is 12 u.

6 / 12 = 0.5

you have 0.5 moles

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Draw the intermediate (in the first box) that forms in the reaction of 1-methylcyclopentene with br2 in ccl4, then draw the expe
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The product of the reaction is 1,2 di-bromo-1-methylcyclopentane.

Explanation:

7 0
3 years ago
Be sure to answer all parts. How many moles of O are needed to combine with 0.276 mole of C to form CO
Vikki [24]

Answer:

0.138 moles of oxygen are needed to combine with 0.276 moles of carbon.

Explanation:

Given data:

Moles of oxygen needed = ?

Moles of carbon present = 0.276 mol

Solution:

Chemical equation:

2C  + O₂      →        2CO

Now we will compare the moles of carbon with oxygen.

              C            :          O₂  

              2            :            1

             0.276     :        1/2×0.276  = 0.138 mol

Thus, 0.138 moles of oxygen are needed to combine with 0.276 moles of carbon.

7 0
3 years ago
How are cancer cells different that normal cells
viva [34]

Answer:

I have that same photo (I always where that combo lol)

Explanation:

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7 0
3 years ago
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What would be the pressure of 1.0g of O2 contained in a 4.00L container at 293 K?
Natalka [10]

Answer: The pressure will be equal to 0.19 atm.

Explanation:

The Ideal Gas Equation states the relationship among the pressure, temperature, volume, and number of moles of a gas.

The equation is:

PV=nRT

where P = pressure in <em>atm</em>

           V = volume in <em>L</em>

           n = numbers of moles of gas in <em>mol</em>

           R = universal gas constant = 0.08206 \frac{L-atm}{mol - K}

           T = temperature in <em>K</em>

Based on the problem,

mass of O2 = 1.0 g

V = 4.00 L

T = 293 K

mol of O2  = ?

P = ?

We need to calculate the moles of O2 before we can use the Ideal Gas Equation. To solve the number of moles, we use the equation:

no. of moles = \frac{given\ mass\ (in\ grams) }{molar\ mass\ (in\ \frac{grams}{mole}) }

The molar mass of O2 is 32 g/mol, therefore,

no. of moles = \frac{1.0g}{32\frac{g}{mol} }

no. of moles of O2 = 0.03125 mol.

Now we substitute the values into the Ideal Gas equation:

P(4.00L) = (0.03125 mol)(0.08206\frac{L-atm}{mol-K} )(293K)

Solving for P, we will get

P=\frac{(0.03125mol)(0.08206\frac{L-atm}{mol-K})(293K) }{4.00L} \\\\P= 0.1878 atm.

In correct significant figures, P is equal to 0.19 atm.

5 0
3 years ago
Pellets of calcium chloride are spread on a sidewalk covered in water that is 36°C. Under which circumstance will the calcium ch
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People walking on the sidewalk crushthe calcium chloride pellets.
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3 years ago
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