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Marysya12 [62]
3 years ago
13

A students drawing of a nitrogen atom is shown. What change would make the model more accurate?

Chemistry
1 answer:
zubka84 [21]3 years ago
8 0

Answer:

C - show 7 neutrons in the nucleus

Explanation:

Use process of elimination:

-Answer A will not work because electrons are not in the nucleus.

-Answer B will change the atom's identity from nitrogen to fluorine; it will not work.

-Answer D will create a nitrogen ion, which is not what the prompt is asking for (an atom); it will not work.

The only logical answer is C, as that is the only one that is also true.

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According to reference table adv-10, which is the strongest reducing agent?
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Li(s)    (answer  A)   
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3 0
3 years ago
What pressure (in atmospheres) does a gas exert when at 385 mm of Hg?
Westkost [7]
To find out the pressure in atm. You must divide 385 by 760. So pressure in atmospheres equals 385/760.
6 0
3 years ago
The first chemists, philosophers like, Aristotle were from which country?
qwelly [4]

Answer:

greece

Explanation:

aristole was particularly from stagria, greece. but most early philosophers are from greece

5 0
3 years ago
Which statement is correct about molarity and volume?
Oksana_A [137]

Answer:

Explanation:

If the choices are:

A. Molarity is defined as moles of solute per liter of solvent.

B. % by mass is defined as grams of solute per 100 g of solvent.

C. % by volume is defined as grams of solute per 100 L of solution.

D. Molarity is defined as moles of solute per liter of solution.

E. All of the above.

then the ans is E

7 0
3 years ago
The solubility of copper chloride at 20 °C is 73 g/100 g of water. Kiera adds 100 g of copper chloride to 100 g of water and sti
OLEGan [10]

Answer:

m_{undissolved}=27g

Explanation:

Hello there!

In this case, according to the given information of the solubility of copper chloride, as the maximum amount of this salt one can dissolve without having a precipitate, we infer that since just 73 grams are actually dissolved, the following amount will remain solid as a precipitate:

m_{undissolved}=100g-73g\\\\m_{undissolved}=27g

Best regards!

3 0
2 years ago
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