Letter A is the characteristic of all chemical change
You would need to utilize Mole ratios found in the adjusted condition;
for each mole of hydrogen utilized, 2 moles of HCl are delivered.
Thusly:
10 mol H2 x 2 mol HCl/1 mol H2 = 20 mol HCL.
For the second question:
you would need to change over 2.0x10^23 particles of Oxygen to moles of oxygen, utilizing Avogadro's number:
2.0x10^23 particles oxygen x 1 mol oxygen/6.022x10^23 atoms oxygen = 0.33 mol Oxygen
utilizing mole proportions once more:
0.66 mol H2O = 2 mol H2O/1 mol Oxygen x 0.33 mol Oxygen
45.0 mol H2O = 2 mol H2O/1 mol Oxygen x 22.5 mol Oxygen
fundamentally to answer stoichiometry, you should take a gander at the adjusted condition to make sense of the mole proportions between components/mixes, and utilizing mole proportions you can change over from moles of one component/compound to moles of another component/compound
Answer:
1.54 x 10⁻¹¹kg
Explanation:
The charge to mass ratio is given as:
1.044 x 10⁻⁸kg/C
Charge on the proton = 1.602 x 10⁻¹⁹C
So;
is the charge to mass ration
e is the charge
m is the mass
1.044 x 10⁻⁸kg/C = 
m = 
= 1.54 x 10⁻¹¹kg
Answer:
At pH 8.59 the precipitation of acid will form.
Explanation:
The pH below which the drug will begin to precipitate can be calculated using the relation
pH = 
where S = total saturation solubility of the drug
S° = solubility of the undissociated species
substituting the respective values in equation, we get:
pH = 8.59
Answer: Option C. The concentration of the reactants is less than that of the product d
Explanation:
