First, you have to find now many moles of octane are present in 191.6g of octane. To do this you need to do this you need to divide 191.6g by its molar mass (which is 114g/mol). This will give you 1.681 moles of octane. Then you need to use the fact that 2 moles of octane are us ed to make 16 moles of carbon dioxide to find how many moles of carbon dioxide 1.681mole of octane produces. To do this you need to multiply 1.681mole by 16/2 to get 13.45mol carbon dioxide. The final step is to find the number of grams presswnt in 13.446 moles of carbon dioxide. To do this you need to multiply 13.446 mole by carbon dioxides molar mass (which is 44g/mol) to get 591.6 g of carbon dioxide.
Therefore, 591.6g of carbon dioxide is produced when 191.6 grams of octane is burned.
I hope this helps. Let me know in the comments if anything is unclear.
Which of the following statements is generally true about change in the workplace ? a ) Most people accept change easily . b) Smart companies can avoid change altogether. c) Change in the workplace fairly infrequently d) Individuals can learn to manage the change in their lives.
<span>The words you seek are soluble and insoluble.The chemical you want is an acid. Add an acid (acetic acid or hydrochloric acid) and the CaCO3 will fizz but CaCl2 will not</span>
Answer:
69.79 mmHg is the pressure for the solution
Explanation:
Formula for vapor pressure lowering:
Vapor pressure of pure solvent(P°) - Vapor pressure of solution (P') = P° . Xm
Xm → Molar fraction of solute (moles of solute / Total moles)
Total moles = Moles of solute + Moles of solvent
Let's determine the moles:
50.36 g . 1mol/342 g = 0.147 moles of sugar
88.69 g. 1mol/ 18g = 4.93 moles of water
Total moles = 0.147 + 4.93 = 5.077 moles
Xm = 0.147 / 5.077 = 0.0289
If we replace data given in the formula:
71.88 mHg - P' = 71.88 mmHg . 0.0289 . 0.0289
P' = - (71.88 mmHg . 0.0289 - 71.88 mmHg)
P' = 69.79 mmHg
