The equation is a circle centered at the origin with radius 8 (sqrt(64))
Therefore, the bounded region is just a quarter circle in the first quadrant.
Riemann Sum: ∑⁸ₓ₋₋₀(y²)Δx=∑⁸ₓ₋₋₀(64-x²)Δx
Definite Integral: ∫₀⁸(y²)dx=∫₀⁸(64-x²)dx
If we draw in OX, OY, OZ we have two congruent right triangles, right angles at the tangent points.
We know XOZ is 132 degrees, which is the meaning of the arc measure
So YOX is half that, 66 degrees.
That leaves 180 - 90 - 66 = 24 degrees for OYX
Angle Y aka XYZ is double that, 48 degrees.
Answer: C
Answer:
(x-7)^2 + (y-2) ^2 = 130
Step-by-step explanation:
We need to find the length of the radius
the length of the radius is found by using the distance formula
r = sqrt( ( -2-7)^2+( -5 -2)^2)
sqrt( ( -9)^2+( -7)^2)
sqrt( 81+49)
sqrt(130)
The formula for a circle is
(x-h)^2 + (y-h) ^2 = r^2
where (h,k) is the center and r is the radius
(x-7)^2 + (y-2) ^2 = 130
or <span>0.857