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3 years ago

Question 3

Physics

2 answers:

Nina [5.8K]3 years ago

7 0

Answer:

20 N

Explanation:

The gravitational force for block B will be given by mg where m is mass of the block and g is gravitational constant, in this case taken as $10 m/s^{2}$

Substituting 2 Kg for m we obtain

Fg=2*10=20 N

Therefore, the gravitational force exerted by block B is nearly 20 N and acts downwards

olganol [36]3 years ago

5 0

The gravitational force exerted on block B : <u>20 N</u>

<h3>Further explanation </h3>

Newton's 2nd law explains that the acceleration produced by the resultant force on an object is proportional and in line with the resultant force and inversely proportional to the mass of the object

$\large {\boxed {\bold {a = \frac {\sum F} {m}}}$

F = force, N

m = mass = kg

a = acceleration m / s²

In this 2-beam system the forces acting on both:

Beam A = mg sin θ and string tension (T)

Beam B = mg and string tension (T)

So the force acting on the system:

mg sin θ -T + T-mg = m.a

Because what is being asked is the gravitational force acting on the block B , then :

F = mg

F = 2 kg. 10 m / s²

F = 20 N

<h3>Learn more </h3>

law of motion

brainly.com/question/75210

displacement of a skateboarder

brainly.com/question/1581159

The distance of the elevator

brainly.com/question/8729508

Keywords: system acceleration, The masses of blocks,friction, the gravitational force

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It is real, inverted, and smaller than the object.

Explanation:

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$\frac{1}{q}=\frac{1}{f}-\frac{1}{p}$

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p = 50 cm is the distance of the object from the lens

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Now let's also write the magnification equation:

$h_i = - h_o \frac{q}{p}$

where

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By substituting p = 50 cm and q = 21.3 cm, we find

$h_i = - h_o \frac{21.3 cm}{50 cm}=-0.43 h_o$

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$h_i < 0$ : this means that the image is inverted

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3 years ago

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Dafna1 [17]

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3 years ago

A person holds a rifle horizontally and fires at a target. The bullet leaves the muzzle of the rifle with a velocity of 460 m/s.

Trava [24]

Answer:

the distance travelled from the bullet to the target is 391m

Explanation:

Hello! To solve this exercise we must follow the following steps.

1. the bullet travels with constant speed which means that the distance traveled to the target is given by the following equation

X=(V1)(T1)

$T1=\frac{X}{V1} =\frac{x}{460}$

where

X=target distance

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T1=

time it takes for the bullet to reach the target

2. The distance the sound travels is given by the following equation (it is the same as the distance from the person to the target)

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target distance

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T2= time it takes the sound of the Bullet to return.

3. The total time it takes for the person to hear the bullet(T=2s) is the sum of the time it takes for the bullet to reach the target, plus the time it takes for the sound to reach the person, with the above we infer the following equation

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4. Finally we use the equations found in step 1 and 2 to find the distance traveled using algebra.

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the distance travelled from the bullet to the target is 391m

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3 years ago