Step-by-step explanation:
In triangles BAD and BCD ,
BD=BD (common)
angle BDA= angle BCD {90°each(given)}
AD=DC (given)
.•. traingle BAD is congruent to triangle BCD (SAS criterion)
Hence , angle A = angle C (CPCT)

<span>
base1= 158.802
</span>

<span>
base2=596.008
the distance travelled = 596.008 - 158.802
= 438 m</span>
Answer: AB = 12.5, BC = 15
<u>Step-by-step explanation:</u>
Perimeter of ΔBCD = BC + CD + BD. Since it is an isoceles triangle, then BC = CD = BD. So, Perimeter of ΔBCD = 3BC
3BC = 45
<u>÷3 </u> <u>÷3 </u>
BC = 15
Perimeter of ΔABC = AB + BC + AC. Since it is an isosceles triangle with BC as the base, then AB = AC. So, Perimeter of ΔABC = 2AB + BC
2AB + BC = 40
2AB + 15 = 40
<u> -15</u> <u> -15 </u>
2AB = 25
<u>÷2 </u> <u>÷2 </u>
AB = 12.5
0.057x 10 is equal to .57. All you have to do is move the decimal to the right one time because there is one zero in 10.
The surface area of the cube is 600cm^2.
6(10^2)
6(100)
600