Almost got it!
x + 3 = 3(y + 2)/2 [Multiplied both sides by 3]
so x + 3 = (3y + 6)/2
2(x + 3) = 3y + 6 [Multiplied both sides by 2]
2x + 6 = 3y + 6
2x = 3y [Subtracted 6 from both sides]
x = 3y/2 [Divided both sides by 2]
x/3 = y/2 [Divided both sides by 3]
So you wrote y/3 instead of y/2
Hope this helped!
Answer:
m ≠1 ( all m in R except 1 )
Step-by-step explanation:
hello :
mx − y + 3 = 0.....(*)
(2m − 1)x − y + 4 = 0 ....(**)
multiply (*) by : -1 you have : -mx+y-3=0 ....(***)
(2m − 1)x − y + 4 = 0 ....(**)
add(***) and(**) : -mx+ (2m − 1)x+1 =0
(2m-m-1)x+1=0
(m-1)x = -1
this system have no solution if : m-1≠0 means : m ≠1
Answer:
2 years: 9 months
We know that, 1 year =12 months
2 years =2×12 months
=24 months
Given
2 years: 9 months
This can be written as
=
9months
24months
=
3months
8months
=8 months :3 months
Hence, 8 months: 3 months is the simplest form of 2 years :9 months
Step-by-step explanation:
Answer:
The experimental probability that a light build chosen at random has no defects is 99.5 % or P(A)=0.995.
Step-by-step explanation:
let S be the sample space for the inspection of the light bulbs.
Therefore, n(s) = 800
let ' A ' be the event of no defects bulbs.
Therefore, n(A) = 796
Now the Experiment probability for a light bulb chosen has no defects will be given by,
![P(A)=\dfrac{n(A)}{n(S)}](https://tex.z-dn.net/?f=P%28A%29%3D%5Cdfrac%7Bn%28A%29%7D%7Bn%28S%29%7D)
Substituting the values we get
![P(A)=\dfrac{796}{800}=0.995](https://tex.z-dn.net/?f=P%28A%29%3D%5Cdfrac%7B796%7D%7B800%7D%3D0.995)
The experimental probability that a light build chosen at random has no defects is 99.5 % or P(A)=0.995.