First, take a look at 3 less than twice x. Twice x would be 2x and 3 less than it would become 2x-3.
Next, 2 more than the quantity 3 times x. The quantity of 3 times x is 3x and 2 more than that would be 3x+2.
Now that we have our two equations, we need to multiply them together, which can be shown as (2x-3)(3x+2).
Then, multiply the two equations together using FOIL (multiply the first two terms, then the outside terms, then inside, and lastly, the last two terms): 2x times 3x, 2x times 2, -3x times 3x, and 2 times -3, which equates to 6x^2+4x-9x-6.
Your final answer is 6x^2-5x-6.
Answer:
Option 2
Step-by-step explanation:
The quantities are not proportional because the line of the graph is both passing through the origin. It might have been proportional if it was passing through the origin.
X=9
A) 3x-7=34
3x= 34+7
3x= 41
x= 41/3
B) x-9=1
x=1+9
x=10
C) dude what is this
D) 4x+5=41
4x=41-5
4x=36
x=36/4
x=9 YAYY
Hope it helps!
#MissionExam001
The question is
if p(x)= 2x³-3x+5, what is the remainder of p(x) divided by (x-5)
We use the synthetic division to find the remainder,
x-5=0
x=5
Now, write the coefficients of polynomial.
5 | 2 0 -3 5
| ↓ 10 50 235
-------------------------------
2 10 47 | 240→ is the remainder.
Quotient= 2x²+10x+47
Remainder= 240
Answer:
9x^4+3x^2 -6
Step-by-step explanation:
(3x^2-2)(3x^2+3)
expand to remove the bracket
9x^4 + 9x^2 -6x^2 - 6
9x^4 + 3x^2- 6