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Step-by-step explanation:
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Answer:
There is a 0.82% probability that a line width is greater than 0.62 micrometer.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.
In this problem
The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a standard deviation of 0.05 micrometer, so
.
What is the probability that a line width is greater than 0.62 micrometer?
That is 
So



Z = 2.4 has a pvalue of 0.99180.
This means that P(X \leq 0.62) = 0.99180.
We also have that


There is a 0.82% probability that a line width is greater than 0.62 micrometer.
Theme and tone work together in that B) theme is a poem's main idea, and tone is the writer's attitude toward that idea.
Answer:
Not enough information. For this to be SAS, the single tick mark would need to be located on the line CB and ED.
Step-by-step explanation:
Let us set up an equation, to determine the list price. X represents the original price
.12 * x = 25
In order to solve for X, you must divide .12 from both sides
x = 25/.12
After you divide, you should get the number 208.33
25/.12 = 208.33
So, the original list price is $208.33