Question

Solve the quadratic equation by using a numeric approach. x squared + 1.1 x minus 2 = 0 a. x = 1.7 and x = -29.2 c. x = 2.3 and x = -22.2 b. x = 3.7 and x = 29.2 d. x = 1.9 and x = -22.2

Answer 1

Answer:

None of the options are correct, the correct answers are: x = 0.967 and -2.067

Step-by-step explanation:

$x^2 + 1.1x - 2 = 0$

Comparing this equation with $ax^2 + bx + c = 0$

a = 1, b = 1.1, c = -2

Using the almighty formula for solving quadratic equation:

$x = \frac{-b \pm \sqrt{b^2 - 4ac} }{2a} \\x = \frac{-1.1 \pm \sqrt{1.1^2 - 4(1)(-2)} }{2(1)} \\x = \frac{-1.1 \pm \sqrt{1.1^2 - 4(1)(-2)} }{2(1)} \\x = \frac{-1.1 \pm 3.035 }{2}\\x_1 = \frac{-1.1 + 3.035 }{2} = 0.967\\x_2 = -\frac{-1.1 - 3.035 }{2} = -2.067$