Answer:
1.a) Cmax = 12μF
b) Cmin = 1.09μF
2.a) E1/E2 = 2
b) E1/E2 = 0.5
Explanation:
For the maximum Capacitance, we have to connect them in parallel. In this configuration, Ct = C1 + C2 + C3 = 12μF
For the minumum Capacitance, we have to connect them in parallel. In this configuration, = 1.09μF
To calculate the energies:
For the minimum capacitance configuration, the charge is the same on all of the capacitors, so:
For the maximum capacitance configuration, the voltage is the same on all of the capacitors, so: