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2 years ago

As a person squeezes and applies pressure to the outside of a balloon, air particles inside

1 answer:

7 0

The air particle inside the balloon will collide more with each other and the temperature inside the balloon will increase.

As a person squeezed and applies the pressure to the outside of a balloon, the air particle inside the balloon gains energy and collide with each other, the particle of the air also try leave the balloon surface will implies equal pressure on the wall of the balloon, as the pressure outside the balloon increase, the inside pressure will also increase.

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Water is poured slowly into the container until the water level has risen into tubes A, B, and C. The water doesn't overflow fro

d1i1m1o1n [39]

Answer:

dA = dB = dC

Explanation:

7 0

2 years ago

uniform electric field of magnitude 365 N/C pointing in the positive x-direction acts on an electron, which is initially at rest

vfiekz [6]

Answer:

a) W = - 1.752 10⁻¹⁸ J, b) U = + 1.752 10⁻¹⁸ J

Explanation:

a) work is defined by

W = F . x

the bold letters indicate vectors, in this case the force is electric

F = q E

we substitute

F = q E x

the charge of the electron is

q = - e

F = - e E x

let's calculate

W = - 1.6 10⁻¹⁹ 365 3 10⁻²

W = - 1.752 10⁻¹⁸ J

b) the change in potential energy is

U = q ΔV

the potential difference is

ΔV = - E. Δs

we substitute

U = - q E Δs

the charge of the electron is

q = - e

U = e E Δs

we calculate

U = 1.6 10⁻¹⁹ 365 3 10⁻²

U = + 1.752 10⁻¹⁸ J

3 0

2 years ago

Please help me on this

Fynjy0 [20]

combustion of fossil fuels would be the correct answer when dealing with the alteration of the carbon cycle.

3 0

3 years ago

One speed skater starts across a frozen lake at an average speed of 8 m/s. Ten seconds later, a second speed skater starts from

Luba_88 [7]

Answer:

40 s

Explanation:

After 10 seconds, the first skater would have a 8m/s * 10s = 80 m head start

Let t be the number of seconds after the second skater starts will the second skater overtake the first skater

The distance traveled by the first skater after t seconds is

$s_1 = v_1t = 8t$

Similarly the distance traveled by the 2nd skater after t seconds is

$s_2 = v_2t = 10t$

Since the 2nd skater catches up to the 1st one after 80 m behind, the distance traveled by the 2nd one must be 80m greater than the distance of the 1st skater

$s_2 = s_1 + 80$