All categories

2 years ago

Needs help please :)

Mathematics

1 answer:

Degger [83]2 years ago

8 0

the thing is I can't see it prop ley:(

You might be interested in

A circle has the center of (1,-5) and a radius of 5 determine the location of the point (4,-1)

Sliva [168]

"determine the location" or namely, is it inside the circle, outside the circle, or right ON the circle?

well, we know the center is at (1,-5) and it has a radius of 5, so the distance from the center to any point on the circle will just be 5, now if (4,-1) is less than that away, is inside, if more than that is outiside and if it's exactly 5 is right ON the circle.

well, we can check by simply getting the distance from the center to the point (4,-1).

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ \stackrel{center}{(\stackrel{x_1}{1}~,~\stackrel{y_1}{-5})}\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{-1})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d = \sqrt{[4-1]^2+[-1-(-5)]^2}\implies d=\sqrt{(4-1)^2+(-1+5)^2} \\\\\\ d = \sqrt{3^2+4^2}\implies d =\sqrt{9+16}\implies d=\sqrt{25}\implies \stackrel{\textit{right on the circle}}{d = 5}$

5 0

3 years ago

Write a formula that describes the value of an initial investment of $1200, growing at an interest rate of 4%, compounded monthl

Flauer [41]

Answer:

f(x)=1200(1.04)^n

Step-by-step explanation:

4 0

3 years ago

PLEASE! GEOMETRY

Rzqust [24]

GF = GH
<F = <H
<E=<G
or
<EGF = <HGJ

answer
<span>e) AAS
</span><span>d) ASA</span>

8 0

3 years ago

Read 2 more answers

Resolve to me these exercises please?

Dima020 [189]

A)4^(n+3)=8^14
2^(2×(n+3))=2^(3×14)
2^(2n+6)=2^42
2^2n=2^36
n=18

b) (assuming a : is divide)
3^(2n+1)=9^17/3^3
3^(2n+1)=3^(2×16)/3^3
3^(2n+1)=3^29
3^2n=3^28
2n=28
n=14

d) (6^n)^4×36=216^10
6^4n×6^2=6^(3×10)
6^(4n+2)=6^30
6^4n=6^28
4n=28
n=7

e)7^(n^2)÷7=49^24
7^(n^2-1)=7^(2×24)
7^(n^2)=7^49
n^2=49
n=7

g)15^(n+4)÷5^(n+4)=81^6
3^(n+4)×5^(n+4)÷5^(n+4)=3^(4×6)
3^(n+4)=3^24
n=20

h)81^n÷9^n+9^(n+2)÷9=90÷9^6
9^2n÷9^n+9^(n+2)÷9=9*10/9^6
9^n+9^(n+1)=10/9^5
I don't know where to go from here

I)what?

7 0

3 years ago

A classroom has a length of 30 ft. and a width of 20 ft. The flooring is to be replaced by tiles. If each tile has a length of 3

Mashcka [7]

Answer:

100

Step-by-step explanation:

Hello! to calculate the number of tiles needed for the floor you need two things

1. number of tiles that fit across the width, this is achieved by dividing the total width by the width of each tile

Width=20ft=240in

$N1=\frac{240}{24} =10$

2.number of tiles that fit in the logitude, this is achieved by dividing the total length by the length of each tile.

leght=30ft=360in

$N2=\frac{360}{36} =10$

Finally, you multiply the number of tiles that fit in width by the number of tiles that fit in length.

N=10X10=100

3 0

3 years ago