ionic bond is formed when two oppositely charged ions attract one another.A covalent bond, also called a molecular bond, is a chemical bond that involves the sharing of electron pairs between atoms.
Answer:
N-ethyl-2-methylpropan-2-amine
Explanation:
In this case, we have to start with the <u>IR info</u>. The signal on 3400 cm^-1 indicates the presence of a <u>hydrogen bonded to the heteroatom</u>. In this case, we have nitrogen in the formula, so we will have the <u>amine group</u>.
On the other hand, we have to analyze the NMR info:
a) We have 2 singlets => This indicates the presence of 2 different hydrogens without neighbors.
b) We have a triplet => This indicates the presence of <u>CH3 bonded to a CH2</u>.
c) We have a quartet => This indicates the presence of <u>CH2 bonded to a CH3</u>.
From b) and c) we can conclude that we have the <u>ethyl group</u> bonded to a nitrogen.
Finally, we have to add 4 more carbons in such a way that we only have a single signal. In this case the <u>ter-butyl group</u>.
In that way, we will have <u>2 singlets</u> (from the CH3 groups in the ter-butyl and the H on the N). Also, we will have the <u>quartet </u>on the CH2 in the ethyl group and the <u>triplet</u> on the CH3 in the ethyl group
They are important because they are the electrons that help the atom to bond with another atom. They are in the outer most shell. ☺️
Answer:
![[A_0]=10\ mg](https://tex.z-dn.net/?f=%5BA_0%5D%3D10%5C%20mg)
![[A_t]=0.08245\ mg](https://tex.z-dn.net/?f=%5BA_t%5D%3D0.08245%5C%20mg)
Explanation:
Given that:
Half life = 10.4 hours
Where, k is rate constant
So,
The rate constant, k = 0.06664 hour⁻¹
Time = 24 hours
Using integrated rate law for first order kinetics as:
![[A_t]=[A_0]e^{-kt}](https://tex.z-dn.net/?f=%5BA_t%5D%3D%5BA_0%5De%5E%7B-kt%7D)
Where,
![[A_t]](https://tex.z-dn.net/?f=%5BA_t%5D)
is the concentration at time t = 2 mg
![[A_0]](https://tex.z-dn.net/?f=%5BA_0%5D)
is the initial concentration = ?
So,
![2\ mg=[A_0]\times e^{-0.06664\times 24}](https://tex.z-dn.net/?f=2%5C%20mg%3D%5BA_0%5D%5Ctimes%20e%5E%7B-0.06664%5Ctimes%2024%7D)
Now, time = 3 days = 3*24 hours = 72 hours ( 1 day = 24 hours)
Thus,
![[A_t]=10\times e^{-0.06664\times 72}\ mg=0.08245\ mg](https://tex.z-dn.net/?f=%5BA_t%5D%3D10%5Ctimes%20e%5E%7B-0.06664%5Ctimes%2072%7D%5C%20mg%3D0.08245%5C%20mg)
