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Bond [772]
3 years ago
10

What is a valence electron and why are they so important to a chemist?

Chemistry
1 answer:
Reika [66]3 years ago
3 0
They are important because they are the electrons that help the atom to bond with another atom. They are in the outer most shell. ☺️
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How many moles of chloride ions are there in 2.5 L of 5 M magnesium chloride?
castortr0y [4]

Answer:

n_{Cl^-}=25molCl^-

Explanation:

Hello,

In this case, since the given 5-M concentration of magnesium chloride is expressed as:

5\frac{molMgCl_2}{L}

We can notice that one mole of salt contains two moles of chloride ions as the subscript of chlorine is two, in such a way, with the volume of solution we obtain the moles of chloride ions as shown below:

n_{Cl^-}=5\frac{molMgCl_2}{L}*\frac{2molCl^-}{1molMgCl_2} *2.5L\\\\n_{Cl^-}=25molCl^-

Best regards.

4 0
2 years ago
When one of the atoms involved in a covalent bond has a much higher electronegativity than the other atom, what type of bond res
ICE Princess25 [194]
If electronegativity difference between atoms is much higher then they form ionic bond.

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5 0
3 years ago
Which of the following IS a valid piece scientific evidence?
Vanyuwa [196]

im sorry it doesn't show

5 0
3 years ago
Using the redox reaction below determine which element is oxidized and which is reduced. 4nh3 + 3ca(clo)2 → 2n2 + 6h2o + 3cacl2
lys-0071 [83]
The oxidation number of elements in equation below are,

                         4NH₃ + 3Ca(ClO)₂ → 2N₂ + 6H₂O + 3CaCl₂

O.N of N in NH₃ = -3
O.N of Ca in Ca(ClO)₂ and CaCl₂ = +2
O.N of N in N₂ = 0
O.N of Cl in Ca(ClO)₂ = +1
O.N of Cl in CaCl₂ = -1

Oxidation:
               Oxidation number of Nitrogen is increasing from -3 (NH₃) to 0 (N₂).

Reduction:
               Oxidation number of Cl is decreasing from +1 [Ca(ClO)₂] to -1 (CaCl₂).

Result:
          <span>N is oxidized and Cl is reduced.</span>
6 0
3 years ago
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6 0
2 years ago
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