Answer: an ex ray and a fire
Explanation:
Answer:
neutral
Explanation:
There are three basic subatomic particles. These are;
- Protons (positively charged)
- Electrons (negatively charged)
- Neutrons (neutral)
A neutron has no charge unlike the proton and the electron. It is present in the nucleus and contributes to the mass of the atom.
Answer:
The solution is 4.93 molal
Explanation:
We assume that solution is aqueous.
We need to apply the colligative property of elevation of boiling point:
ΔT = Kb . m . i
ΔT = Boiling T° of solution - Boiling T° of pure solvent
110.1°C - 100°C = 10.1°C
Kb = 0.512 °C/m
m = molality → unknown
i = Van't Hoff factor (numbers of ions dissolved)
We assume 100 % dissociation: CoCl₃ → Co³⁺ + 3Cl⁻ i = 4
We have 1 mol of Co³⁺ + 3 moles of chlorides
We replace data → 10.1°C = 0.512°C/m . m . 4
10.1°C / (0.512 m/°C . 4) = m → 4.93
Answer:
https://courses.lumenlearning.com/sanjacinto-atdcoursereview-chemistry1-1/chapter/formula-mass-and-the-mole-concept/
Explanation:
https://courses.lumenlearning.com/sanjacinto-atdcoursereview-chemistry1-1/chapter/formula-mass-and-the-mole-concept/
the answer should be in there
<em>Acetic acid, HC2H3O2</em>
First, calculate for the molar mass of acetic acid as shown below.
M = 1 + 2(12) + 3(1) + 2(16) = 60 g
Then, calculating for the percentages of each element.
<em> Hydrogen:</em>
P1 = ((4)(1)/60)(100%) = <em>6.67%</em>
<em> Carbon:</em>
P2 = ((2)(12)/60)(100%) = <em>40%</em>
<em>Oxygen</em>
P3 =((2)(16) / 60)(100%) = <em>53.33%</em>
<em>Glucose, C6H12O6</em>
The molar mass of glucose is as calculated below,
6(12) + 12(1) + 6(16) = 180
The percentages of the elements are as follow,
<em> Hydrogen:</em>
P1 = (12/180)(100%) = <em>6.67%</em>
<em>Carbon:</em>
P2 = ((6)(12) / 180)(100%) = <em>40%</em>
<em>Oxygen:</em>
P3 = ((6)(16) / 180)(100%) = <em>53.33%</em>
b. Since the empirical formula of the given substances are just the same and can be written as CH2O then, the percentages of each element composing them will just be equal.