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Naddika [18.5K]
3 years ago
8

A(n) _____ is a statement whose proof can be deduced directly from a previous theorem. auxiliary line remote interior angle coro

llary triangle 5) A triangle in which one of its interior angles is an obtuse angle is a(n) _____ triangle. equiangular right obtuse acute 6) A triangle with at least two congruent sides is a(n) _____ triangle. right auxiliary isosceles equiangular
Mathematics
1 answer:
bekas [8.4K]3 years ago
8 0

Answer:

The words in order are:

  • corollary
  • obtuse
  • isosceles

Step-by-step explanation:

A corollary is a quick conclusion of a theorem. The proof of a corollary is rather short, compared to the proofs of theorems and other propositions. For example, if you consider the theorem "the area of a circle of radius r is πr²" then an inmediate corollary is "the area of a semicircle of radius r is πr²/2".

Triangles can be classified according to their interior angles. The three types of triangles are acute, right and obtuse. Obtuse triangles are those that have an inner obtuse (>90°) angle. Right triangles have an inner right (=90°) angle, and acute triangles have 3 acute (<90°) inner angles.

Similarly, triangles can be classified according to their sides, as equilateral, isosceles and scalene. Equilateral triangles have all their 3 congruent sides, isosceles triangles have at least 2 congruent sides, and scalene triangles have no congruent sides.

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The sum of four consecutive odd integerd is -72.
Solnce55 [7]

n, n + 2, n + 4, n + 6 - four consecutive odd integers

-72 - the sum

The equation:

n + (n + 2) + (n + 4) + (n + 6) = -72

n + n + 2 + n + 4 + n + 6 = -72

4n + 12 = -72     |subtract 12 from both sides

4n = -84     |divide both sides by 4

n = -21

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n + 4 = -21 + 4 = -17

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Consider this expression.
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What is the relationship between 0.006 and 0.06?
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Suppose that a password for a computer system must have at least 8, but no more than 12, characters, where each character in the
uranmaximum [27]

Part a)

There are 52 letters (26 lowercase and 26 uppercase), 10 digits, and 6 symbols. There are 52+10+6 = 68 different characters to choose from.

  • If there are 8 characters for this password, then we have 68^8 = 4.5716 * 10^14 different passwords possible.
  • If there are 9 characters, then we have 68^9 = 3.1087 * 10^16 different passwords
  • If there are 10 characters, then we have 68^10 = 2.1139 * 10^18 different passwords
  • If there are 11 characters, then we have 68^11 = 1.4375 * 10^20 different passwords
  • If there are 12 characters, then we have 68^12 = 9.7748 * 10^21 different passwords

Adding up those subtotals gives

68^8+68^9+68^10+68^11+68^12 = 9.9207 * 10^21

different passwords possible.

<h3>Answer: Approximately 9.9207 * 10^21 </h3>

======================================================

Part b)

Let's find the number of passwords where we don't have a special symbol

There are 52+10 = 62 different characters to pick from

  • If there are 8 characters for this password, then we have 62^8 = 2.1834 * 10^14 different passwords possible.
  • If there are 9 characters, then we have 62^9 = 1.3537 * 10^16 different passwords
  • If there are 10 characters, then we have 62^10 = 8.3930 * 10^17 different passwords
  • If there are 11 characters, then we have 62^11 = 5.2037 * 10^19 different passwords
  • If there are 12 characters, then we have 62^12 = 3.2263 * 10^21 different passwords

Adding those subtotals gives

62^8+62^9+62^10+62^11+62^12 = 3.2792 * 10^21

different passwords where we do not have a special character. Subtract this from the answer in part a) above

( 9.9207 * 10^21)  - (3.2792 * 10^21) = 6.6415 * 10^21

which represents the number of passwords where we have one or more character that is a special symbol. I'm using the idea that we either have a password with no symbols, or we have a password with at least one symbol. Adding up those two cases leads to the total number of passwords possible.

<h3>Answer: Approximately 6.6415 * 10^21</h3>

======================================================

Part c)

The answer from part a) was roughly 9.9207 * 10^21

It will take about 9.9207 * 10^21  nanoseconds to try every possible password from part a).

Divide 9.9207 * 10^21  over 1*10^9 to convert to seconds

(9.9207 * 10^21 )/(1*10^9) = 9,920,700,000,000

This number is 9.9 trillion roughly.

It will take about 9.9 trillion seconds to try every password, if you try a password per second.

------

To convert to hours, divide by 3600 and you should get

(9,920,700,000,000)/3600 = 2,755,750,000

So it will take about 2,755,750,000 hours to try all the passwords.

------

Divide by 24 to convert to days

(2,755,750,000)/24= 114,822,916.666667

which rounds to 114,822,917

So it will take roughly 114,822,917 days to try all the passwords.

------

Then divide that over 365 to convert to years

314,583.334246576

which rounds to 314,583

It will take roughly 314,583 years to try all the passwords

------------------------------

<h3>Answers:</h3>
  • 9.9 trillion seconds
  • 2,755,750,000 hours
  • 114,822,917 days
  • 314,583 years

All values are approximate, and are roughly equivalent to one another.

5 0
3 years ago
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