1.For each of the following, give the name of an element from Period 4 (potassium to krypton), which matches the description.
Elements may be used once, more than once or not all.. Single line text.
(1 Point)
an element that reacts with water to produce a lilac flame
2.For each of the following, give the name of an element from Period 4 (potassium to krypton), which matches the description.
Elements may be used once, more than once or not all.. Single line text.
(1 Point)
an element used as an inert atmosphere
3.For each of the following, give the name of an element from Period 4 (potassium to krypton), which matches the description.
Elements may be used once, more than once or not all.. Single line text.
(1 Point)
an element that has a valency of 3
4.Write a balanced chemical equation for the reaction between potassium and water. (Non-anonymous question). .
(1 Point)
Upload file
File number limit: 1Single file size limit: 10MBAllowed file types: Word, Excel, PPT, PDF, Image, Video, Audio
5.For each of the following, give the name of an element from Period 4 (potassium to krypton), which matches the description.
Elements may be used once, more than once or not all.. Single line text.
(1 Point)
an element with a fixed valency of 2 that not is not in group 2
HELP
There are 4/7 boys, so there are 3/7 girls.
Let the total number of children be x.
4/7x = 8
1/7x = 8 ÷ 4
1/7x = 2
3/7x = 2 x 3
3/7x = 6
There are 6 girls.
First factor 175:
1, 5, 5, 7
Now that we know the factors of 175, combine common factors:
1, 5², 7
Hope this helps!
I believe it’s the first one. 1.5 + 2 = 3.5
its not worth 25 points but ok here u go let's solve your equation step-by-step.
3y−1=13−4y
Step 1: Simplify both sides of the equation.
3y−1=13−4y
3y+−1=13+−4y
3y−1=−4y+13
Step 2: Add 4y to both sides.
3y−1+4y=−4y+13+4y
7y−1=13
Step 3: Add 1 to both sides.
7y−1+1=13+1
7y=14
Step 4: Divide both sides by 7.
7y
7
=
14
7
y=2
Answer:
y=2 so there your answer is this equation has one solution your welcome
