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anzhelika [568]
3 years ago
12

What are some ways to describe the relationship between sets of numbers?

Mathematics
1 answer:
Tamiku [17]3 years ago
5 0
Even numbers odd numbers prime numbers composite numbers (I tried)
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-5(x - 1) = – 7(x+3)<br> whats the answer
VARVARA [1.3K]

Answer:

x = -13

Step-by-step explanation:

-5(x - 1) = -7(x + 3)

Distribute on both sides.

-5x + 5 = -7x - 21

Add 7x to both sides.

2x + 5 = -21

Subtract 5 from both sides.

2x = -26

Divide both sides by 2.

x = -13

8 0
3 years ago
Talib is trying to find the inverse of the function to the right. His work appears beneath it. Is his work correct? Explain your
aev [14]
The answer is is 3 hope it helps
6 0
3 years ago
What is the estimated product of 1.39 x 6.76?
qwelly [4]

Answer:

7

Step-by-step explanation:

5 0
3 years ago
Please help me with these factoring problems. Please help me solve. I can't do these!!
aleksley [76]
Simple...

you have: 

1.) -8x-16  --->>>

Factor out a -8 -->>

-8(x+2)

2.)9d+15db --->

Factor out 3d -->

3d(3+5b)

3.) 2a-9ax-->>

Factor out -a -->

-1a(9x-2)

Thus, your answer.
3 0
3 years ago
Please explain your answer. THX!!!!
Sidana [21]

Answer:

1)cos(x)sin^{2}x

2)0

Step-by-step explanation:

for part 1:

Given cos(x) - cos^3(x)

= cos(x) (1- cos^2(x))

Using the identity cos^{2}x +sin^{2}x=1\\ sin^{2}x=1-cos^{2}x

= cos(x)sin^2(x)

for part 2:

given

=cos\frac{5\pi }{8}cos\frac{\pi }{8}  + sin\frac{5\pi }{8}sin\frac{\pi }{8}

Using the identity cos(a)cos(b) + sin(a)sin(b)= cos(a-b)

=cos(\frac{5\pi }{8} -\frac{\pi }{8})

=cos\frac{4\pi }{8}

=cos\frac{\pi }{2}

=0!

5 0
3 years ago
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