4X-4Y>28
X-Y>7 both side divide by 4
See it is < and not ≤ so we don't include -4
put a circle around -4 but don't shade it in
to get there, move 4 units left from 0
then we see x is less than -4
so shade to the left of the circle
Answer:
m∠BDC = 43°
Step-by-step explanation:
According to the theorem every peripheral angle in the circle is equal to half value of central angle.
Angle m∠ADB is corresponding peripheral angle of central angle m∠AOB.
According to this m∠AOB = 2· m∠ADB = 2· 43 = 86°
If angle m∠BOC=m∠AOB= 86°
Angle m∠BDC is corresponding peripheral angle of central angle m∠BOC
According to this m∠BDC = m∠BOC/2 = 43°
Good luck!!!
Answer:
x = 15
Step-by-step explanation:
4x is congruent to 45 + 15
4x = 45 + 15
simplify 4x = 60
divide both sides by 4 x = 15
F(g(2)) = 3(x^3 + 1)^2 - 7 = 3(x^6 + 2x^3 + 1) - 7 = 3x^6 + 6x^3 + 3 - 7 = 3x^6 + 6x^3 - 4
