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RoseWind [281]
2 years ago
9

2. All of the girls in Danielle’s cabin at camp are the same age. Their counselor is 3 times their age. Danielle’s age and her c

ounselor’s ages add up to 28. Write and solve an equation that can be used to find the ages of Danielle and her counsel
Mathematics
1 answer:
Aloiza [94]2 years ago
4 0

Answer:

Danielle is 7 and her counselor is 21

Step-by-step explanation:

Let x be the age of Danielle and y be the age of her counselor then:

y=3x

x+y=28

We can solve this using substitution. In this case, substitute 3x for y since y=3x...

x+3x=28

   4x=28

Divide both sides by 4 (division property of equality)

x=7

y=3x=3(7)=21

Danielle is 7 and her counselor is 21

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Find the area of the composite figure
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Answer:

48 ft^2

Step-by-step explanation:

5.5 times 6 equals 33 (larger square part)

2.5 times 6 equals 15 (two triangles combined so you dont have to 1/2)

4 0
3 years ago
Write the equation of a line that is parallel to {x=8}x=8x, equals, 8 and that passes through the point {(-3,-2)}(−3,−2)left par
Alexxandr [17]

Answer:

  x = -3

Step-by-step explanation:

The line parallel to x=8 is another vertical line:

  x = constant

To make it go through a point with an x-coordinate of -3, the constant must be -3.

Your line is ...

  x = -3

5 0
3 years ago
How many sides do 2 nonagons and 3 decagons have in all?
SVETLANKA909090 [29]

Answer:

48 sides

Step-by-step explanation:

A nonagon has 9 sides

A decagon has 10 sides

10 + 10 + 10 = 30

9+9 = 18

30 + 18 = 48

48 sides in total

Give brainliest please!
Hope this helps :)

8 0
2 years ago
16) Please help with question. WILL MARK BRAINLIEST + 10 POINTS.
Katyanochek1 [597]
We will use the sine and cosine of the sum of two angles, the sine and consine of \frac{\pi}{2}, and the relation of the tangent with the sine and cosine:

\sin (\alpha+\beta)=\sin \alpha\cdot\cos\beta + \cos\alpha\cdot\sin\beta

\cos(\alpha+\beta)=\cos\alpha\cdot\cos\beta-\sin\alpha\cdot\sin\beta

\sin\dfrac{\pi}{2}=1,\ \cos\dfrac{\pi}{2}=0

\tan\alpha = \dfrac{\sin\alpha}{\cos\alpha}

If you use those identities, for \alpha=x,\ \beta=\dfrac{\pi}{2}, you get:

\sin\left(x+\dfrac{\pi}{2}\right) = \sin x\cdot\cos\dfrac{\pi}{2} + \cos x\cdot\sin\dfrac{\pi}{2} = \sin x\cdot0 + \cos x \cdot 1 = \cos x

\cos\left(x+\dfrac{\pi}{2}\right) = \cos x \cdot \cos\dfrac{\pi}{2} - \sin x\cdot\sin\dfrac{\pi}{2} = \cos x \cdot 0 - \sin x \cdot 1 = -\sin x

Hence:

\tan \left(x+\dfrac{\pi}{2}\right) = \dfrac{\sin\left(x+\dfrac{\pi}{2}\right)}{\cos\left(x+\dfrac{\pi}{2}\right)} = \dfrac{\cos x}{-\sin x} = -\cot x
3 0
3 years ago
Me. Silvera bought a can of paint. He used 3/8 of it to paint a fence and 1/4 to paint a table top. He painted a chair with some
LuckyWell [14K]
Well, seeing the information above, he used 5/8 of paint to paint the fence and table top. If he only had 1/8 left of the paint, he used 2/8 on the chair.

I found the 5/8 because I needed a common denominator. I multiplied the top and bottom by 2 to get 2/8. 3/8+2/8=5/8, and then I added 2/8 to the 5/8 that then gave me 7/8 of paint used, and 1/8 of paint left. 

Hope I helped!
3 0
4 years ago
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