The electric force between two charge objects is calculated through the Coulomb's law.
F = kq₁q₂/d²
The value of k is 9.0 x 10^9 Nm²/C² and the charge of proton is 1.602 x10^-19 C. Substituting the known values from the given,
2.30x10^-26 = (9.0 x 10^9 Nm²/C²)(1.602 x10^-19C)²/d²
The value of d is equal to 0.10 m.
Answer:
1225 J
Explanation:
The Gravitational potential energy (PEG) gained by a mass lifted above the ground is given by
where
m is the mass
g = 9.8 m/s^2 is the acceleration due to gravity
h is the height at which the object has been lifted
In this problem, we have
m = 250 kg
h = 0.5 m
So, the PE of the object is
Explanation:
As the given data is as follows.
ohm, ohm,
= 1200 (as 1 k ohm = 1000 m)
(a) We will calculate the maximum resistance by combining the given resistances as follows.
Max. Resistance =
= ohm
= 2600 ohm
or, = 2.6 ohm
Therefore, the maximum resistance you can obtain by combining these is 2.6 ohm.
(b) Now, the minimum resistance is calculated as follows.
Min. Resistance =
=
= ohm
Hence, we can conclude that minimum resistance you can obtain by combining these is ohm.