- <em>m</em><em>ahalaga ito upang mas mapaliwanag mo ng maayos at klaro ang isang bagay o pangyayari.</em>
<em>sana </em><em>makatulong</em><em> </em><em>hehe</em>
Given that,
Mass of student 1, m₁ = 90 kg
Mass of student 2, m₂ = 60 kg
Speed of student 1, v₁ = 5 m/s
To find,
The velocity of the other student.
Solution,
Using the conservation of momentum to find the velocity of the other student. Let it is v₂.
So, the velocity of the other student is 7.5 m/s.
Answer:
Your answer will be 600meters
(a) The velocity ratio of the screw is 1570.8.
(b) The mechanical advantage of the screw is 785.39.
<h3>
Velocity ratio of the screw</h3>
The velocity ratio of the screw is calculated as follows;
V.R = 2πr/P
where;
- P is the pitch = 1/10 cm = 0.1 cm = 0.001 m
- r is radius = 25 cm = 0.25 m
V.R = (2π x 0.25)/(0.001)
V.R = 1570.8
<h3>Mechanical advantage of the screw</h3>
E = MA/VR x 100%
0.5 = MA/1570.8
MA = 785.39
Learn more about mechanical advantage here: brainly.com/question/18345299
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If there is no friction, the force that moves the box forward horizontally must be matched by the same force.
If there is friction, then the force moving it forward = frictional force + the additional force you need to add.