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Margaret [11]
4 years ago
15

When light passes from a faster medium into a slower medium, which of the following explains what will occur?

Physics
2 answers:
tester [92]4 years ago
7 0

Answer:

It would be B

Explanation:

beks73 [17]4 years ago
5 0

When light passes from a faster medium into a slower medium, light will be refracted toward a line drawn perpendicular to the point of refraction. <em>(B)</em>

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A metal sphere is neutral because it has an equal number of protons and electrons. Draw how the charges in the sphere are redist
Anika [276]

Answer:

https://www.google.com/search?q=A+metal+sphere+is+neutral+because+it+has+an+equal+number+of+protons+and+electrons.+Draw+how+the+charges+in+the+sphere+are+redistributed+when+a+negatively+charged+rod+is+brought+near+it.&source=lnms&tbm=isch&sa=X&ved=0ahUKEwiixouw2IDiAhUIbawKHaYzBaMQ_AUIDigB&biw=1455&bih=688#imgrc=3YSBhnGs0Hz80M:

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6 0
3 years ago
Read 2 more answers
What is the ratio of the sun’s gravitational pull on Mercury to the sun’s gravitational pull on the earth?
Marta_Voda [28]

Answer:

The answer is \frac{F_{Sun-Mercury} }{F_{Sun-Earth} } =0,3709. Let's learn why.

Explanation:

Newton's law of universal gravitation says;

F_{g} =G.\frac{m_{1}.m_{2}}{r^{2}}

Here G is a universal gravitational <u>constant</u> and is measured experimentally.

Sun's gravitational pull on mercury is:

F_{Sun-Mercury} =G.\frac{m_{sun}.3,30.10^{23}}{(5,79.10^{10})^{2} }

Therefore F_{Sun-Mercury} = Gm_{sun} 98,4366

Sun's gravitational pull on Earth is:

F_{Sun-Earth} =G.\frac{m_{sun} 5,97.10^{24} }{(1,50.10^{11}) ^{2}}

Therefore F_{Sun-Earth} =Gm_{sun} 265,33

As a result;

\frac{F_{Sun-Mercury}}{F_{Sun-Earth} }=\frac{Gm_{sun}98,4366}{Gm_{sun}265,33 } =0,3709

4 0
4 years ago
How do you work out Potential Difference??? <br> Please can you make it simple :) <br> Thanks.
patriot [66]

Answer:

Potential difference is the work done in moving a positive test charge from infinity to the point in question.

Voltage is an expression of PD.   (Joules / Coulomb)

Say that a capacitor has a PD of 5 Volts. The work in moving a positive test charge from the positive plate to the negative plate is -5 Joules/Coulomb or -5 volt. (At the positive plate the positive test charge (1 Coulomb) already has a PD of + 5 Volts.)

7 0
3 years ago
In the diagram, what is happening to the temperature at Point B? Question 6 options: A. The temperature is rising as the molecul
raketka [301]
<span> B. The temperature is not rising because the heat is being used to break the connections between the molecules </span>
6 0
3 years ago
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Calculate the amount of heat needed to melt 35.0 g of ice at 0 ºC.Express your answer in kilojoules
PolarNik [594]
The amount of heat will be equal to Lm.

Where L is the latent heat of fusion and m is mass of the ice.

Latent heat of ice = 80cal/g.

So the amount of heat required here will be 35× 80cal

= 2,800 cal.
6 0
3 years ago
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