Mass is the same, weight is less
<h3>What is the Weight and mass on Moon ?</h3>
As we know that the mass of the object is the measurement of the quantity of the matter that is present in it
So here we can say that if the mass of the object is m then its total quantity of the matter that is present in it is given as
mass = (density) × (volume)
Now for the weight of the object is defined as the force of gravity due to planet
Fg = mg
so the weight of the object is depending on the acceleration due to gravity of the planet
As we know that the gravity of moon is smaller than the gravity of the earth so here weight on the moon will be smaller than the weight on the Earth
Learn more about Weight on Moon here:
brainly.com/question/4080619
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It's the Doppler Effect that "up and down sound."
I was on Yahoo--- Brainly doesn't have an option for Credientials or Site credit, so I'll just put this in the quotes:
<span>The formula for doppler effect is always (s is speed and f is frequency): </span>
<span>f_perceived.by.observer = f_of.emitted.wave * (s_wave + s_observer) / (s_wave + s_source.of.wave) </span>
<span>And you should pay attention to the signs: </span>
<span>s_observer is positive if the receiver is moving towards the source, negative otherwise </span>
<span>s_source.of.wave is positive if the source is moving away from the observer, negative otherwise </span>
<span>Applying it to this case: </span>
<span>s_source.of.wave = ? (positive), speed of ambulance </span>
<span>s_observer = + 2.44 m/s speed cyclist </span>
<span>f_of.emitted.wave =1800 Hz frequency of whine </span>
<span>f_perceived.by.observer = 1760 frequency heard by cyclist </span>
<span>s_wave = 343 m/s speed of sound in air </span>
<span>Now you know every value in the equation for doppler effect except by s_source.of.wave, so you can solve for s_source.of.wave.</span>
Answer:
The force required to push to stop the car is 288.67 N
Explanation:
Given that
Mass of the car, m = 1000 kg
Initial speed of the car, u = 1 m/s
The car and push on the hood at an angle of 30° below horizontal,
Distance, d = 2 m
Let F is the force must you push to stop the car.
According work energy theorem theorem, the work done is equal to the change in kinetic energy as :
The force required to push to stop the car is 288.67 N
Answer:
m g = G * m * M / R^2 force of attraction
g = G * M / R^2
g = 6.67E-11 * 5.96E24 / (6.37E6)^2
g = 6.67 * 5.96 / 6.37^2 * 10^1
g = .98 * 10 = 9.8 m/s^2
Q2.
d g = G M * (-2 R^-3 dR ) = -2 G M / R^3 (very small where dR = 1)