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3 years ago

a snail takes 16 minutes 40 seconds to cover a distance of 1 m calculate the average speed of the swimmer

Physics

2 answers:

matrenka [14]3 years ago

8 0

The snail’s speed is 0.001042. Hope this helps!

77julia77 [94]3 years ago

5 0

<h2>Answer: </h2>

<u><em>1 cm per 10 seconds </em></u>

<h2>Explanation: </h2>

<em>16 minutes and 40 seconds is 1000 seconds so take the 1 meter turn it into 100 centimeters then divide both sides by 100 and you get your answer which is </em><u><em>1 centimeter every 10 seconds.</em></u>

<em />

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Answer:

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3 years ago

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A tank of water is in the shape of a cone (assume the ""point"" of the cone is pointing downwards) and is leaking water at a rat

Inessa05 [86]

Answer:

a) dh/dt = -44.56*10⁻⁴ cm/s

b) dr/dt = -17.82*10⁻⁴ cm/s

Explanation:

Given:

Q = dV/dt = -35 cm³/s

R = 1.00 m

H = 2.50 m

if h = 125 cm

a) dh/dt = ?

b) dr/dt = ?

We know that

V = π*r²*h/3

and

tan ∅ = H/R = 2.5m / 1m = 2.5 ⇒ h/r = 2.5

⇒ h = (5/2)*r

⇒ r = (2/5)*h

If we apply

Q = dV/dt = -35 = d(π*r²*h/3)*dt

⇒ d(r²*h)/dt = 3*35/π = 105/π ⇒ d(r²*h)/dt = -105/π

a) if r = (2/5)*h

⇒ d(r²*h)/dt = d(((2/5)*h)²*h)/dt = (4/25)*d(h³)/dt = -105/π

⇒ (4/25)(3*h²)(dh/dt) = -105/π

⇒ dh/dt = -875/(4π*h²)

b) if h = (5/2)*r

Q = dV/dt = -35 = d(π*r²*h/3)*dt

⇒ d(r²*h)/dt = d(r²*(5/2)*r)/dt = (5/2)*d(r³)/dt = -105/π

⇒ (5/2)*(3*r²)(dr/dt) = -105/π

⇒ dr/dt = -14/(π*r²)

Now, using h = 125 cm

dh/dt = -875/(4π*h²) = -875/(4π*(125)²)

⇒ dh/dt = -44.56*10⁻⁴ cm/s

then

h = 125 cm ⇒ r = (2/5)*h = (2/5)*(125 cm)

⇒ r = 50 cm

⇒ dr/dt = -14/(π*r²) = - 14/(π*(50)²)

⇒ dr/dt = -17.82*10⁻⁴ cm/s

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3 years ago

a snail takes 16 minutes 40 seconds to cover a distance of 1 m calculate the average speed of the swimmer​

a snail takes 16 minutes 40 seconds to cover a distance of 1 m calculate the average speed of the swimmer