Question

A rectangle has a height of 777 and a width of 2x^2-32x

Answer 1

Explanation:

Hello! Remember you have to write clear questions in order to get good and exact answers. Here I'll assume the data given in a comment above. So:

$H:height \\ \\ W:Width \\ \\ \\ H=7 \\ \\ W= 2x^2-32x+2$

We know that the area (A) of any rectangle is given by:

$A=H\times W \\ \\ A=7(2x^2-32x+2) \\ \\ \\ Expanding: \\ \\ A=(7)(2x^2)-(7)(32x)+(7)(2) \\ \\ \boxed{A=14x^2-224x+14}$