All categories

3 years ago

0.00082350 as scientific notation. WILL GIVE BRAINLEST

Mathematics

1 answer:

mezya [45]3 years ago

6 0

Answer:8.83 × 10 − 3

Step-by-step explanation:

You might be interested in

Identify the circumference of ⊙S in which A=64π ft^2. HELP ASAP!!

Vika [28.1K]

Answer:

C = 16π ft

Step-by-step explanation:

If we know the area

A = pi r^2

64 pi = pi r^2

Divide each side by pi

64 = r^2

Take the square root of each side

8 = r

The radius is 8

Now we can find the circumference

C = 2 *pi*r

C = 2*pi*8

C = 16pi

5 0

2 years ago

Read 2 more answers

12⋅(4−24−4) anyone got the answer

serg [7]

Answer will be -24
+4-24-4 = -24

6 0

2 years ago

Read 2 more answers

Which one you think is the right one? <br><br> (No link pls)

Montano1993 [528]

Answer:

You are correct, it is B.

Step-by-step explanation:

5 0

2 years ago

The heights (measured in inches) of men aged 20 to 29 follow approximately the normal distribution with mean 69.3 and standard d

Zolol [24]

Answer:

The middle 92% of all heights fall between 64.4 inches and 74.2 inches.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 69.3, \sigma = 2.8$

Between what two values does that middle 92% of all heights fall?

The middle 92% falls from X when Z has a pvalue of 0.5 - 0.92/2 = 0.04 to X when Z has a pvalue of 0.5 + 0.92/2 = 0.96. So from the 4th percentile to the 96th percentile.

4th percentile

X when $Z = -1.75$

$Z = \frac{X - \mu}{\sigma}$

$-1.75 = \frac{X - 69.3}{2.8}$

$X - 69.3 = -1.75*2.8$

$X = 64.4$

96th percentile

X when $Z = 1.75$

$Z = \frac{X - \mu}{\sigma}$

$1.75 = \frac{X - 69.3}{2.8}$

$X - 69.3 = 1.75*2.8$

$X = 74.2$

The middle 92% of all heights fall between 64.4 inches and 74.2 inches.

6 0

3 years ago

Express

Ann [662]

◆ NUMBER SYSTEMS ◆

$\frac{7 - 3 \sqrt{3} }{2 + \sqrt{3} } \\ \\ rationalising \: the \: denominator \: , \\ \\ \frac{7 - 3 \sqrt{3} }{2 + \sqrt{3} } \times \frac{2 - \sqrt{3} }{2 - \sqrt{3} } \\ \\ = \frac{(7 - 3 \sqrt{3})(2 - \sqrt{3}) }{ {2}^{2} - { \sqrt{3} }^{2} } \\ \\ = \frac{14 - 7 \sqrt{3} - 6 \sqrt{3} + 9 }{4 - 3} \\ \\ = \frac{23 - 13 \sqrt{3} }{1} \\ \\ = 23 - 13 \sqrt{3} = a + b \sqrt{3} \\ \\ comparing \: both \: sides \: , \\ we \: get \: , \\ \\ a = 23 \\ and \: , \: \\ b = - 13$

8 0

2 years ago