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WINSTONCH [101]
3 years ago
9

In the figure,ABC is congruent to ADC . If the square ABCD is dilated by a factor of 2 to form A'B'C'D', what is the ratio of th

e area ofA'B'C'D' to the area of ABCD?
Mathematics
2 answers:
DaniilM [7]3 years ago
8 0
In the figure,ABC is congruent to ADC . If the square ABCD is dilated by a factor of 2 to form A'B'C'D', the ratio of the area of A'B'C'D' to the area of ABCD is 1/2. Since the dilation is by a factor of 2, so the area of the A'B'C'D' should be smaller than the area of ABCD.
Makovka662 [10]3 years ago
8 0

Answer:

for plato or gradpoint answer is 4:1 i got it correct :)

Step-by-step explanation:

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Please help. Thank you
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Given:

PQRS\sim TUVW

In the given figure, PS=x, RS=35, UV=20, VW=25 and TW=15

To find:

The scale factor from PQRS to TUVW.

Solution:

We have,

PQRS\sim TUVW

We know that the corresponding sides of similar figures are proportional. The scale factor is the ratio of one side of image and corresponding side of preimage.

The scale factor is:

k=\dfrac{VW}{RS}

k=\dfrac{25}{35}

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Step-by-step explanation:

Pov:شما به ترجمه گوگل رفت برای دیدن آنچه من گفتم و دیدم این xD

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