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WINSTONCH [101]
3 years ago
9

In the figure,ABC is congruent to ADC . If the square ABCD is dilated by a factor of 2 to form A'B'C'D', what is the ratio of th

e area ofA'B'C'D' to the area of ABCD?
Mathematics
2 answers:
DaniilM [7]3 years ago
8 0
In the figure,ABC is congruent to ADC . If the square ABCD is dilated by a factor of 2 to form A'B'C'D', the ratio of the area of A'B'C'D' to the area of ABCD is 1/2. Since the dilation is by a factor of 2, so the area of the A'B'C'D' should be smaller than the area of ABCD.
Makovka662 [10]3 years ago
8 0

Answer:

for plato or gradpoint answer is 4:1 i got it correct :)

Step-by-step explanation:

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Let f(x)= x(2x-3)/(x+2)x. Find the domain, vertical and horizontal asymptote
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Step-by-step explanation:

Domain of a rational function is everywhere except where we set vertical asymptotes. or removable discontinues

Here, we have

\frac{x(2x - 3)}{(x + 2)x}

First, notice we have x in both the numerator and denomiator so we have a removable discounties at x.

Since, we don't want x to be 0,

We have a removable discontinuity at x=0

Now, we have

\frac{2x - 3}{x + 2}

We don't want the denomiator be zero because we can't divide by zero.

so

x + 2 = 0

x =  - 2

So our domain is

All Real Numbers except-2 and 0.

The vertical asymptors is x=-2.

To find the horinzontal asymptote, notice how the numerator and denomator have the same degree. So this mean we will have a horinzontal asymptoe of

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So that becomes

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So we have a horinzontal asymptofe of 2

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Leona [35]
The answer is 2
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What is 24 as a percentage of 200
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Step-by-step explanation:

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vovikov84 [41]

Answer:

See explanation

Step-by-step explanation:

Polygon WXYZ has vertices W(-1.5, 1.5), X(6, 1.5), Y(6, -4.5), and Z(-1.5, -4.5).

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