Question

In the figure,ABC is congruent to ADC . If the square ABCD is dilated by a factor of 2 to form A'B'C'D', what is the ratio of the area ofA'B'C'D' to the area of ABCD?

Answer 1

In the figure,ABC is congruent to ADC . If the square ABCD is dilated by a factor of 2 to form A'B'C'D', the ratio of the area of A'B'C'D' to the area of ABCD is 1/2. Since the dilation is by a factor of 2, so the area of the A'B'C'D' should be smaller than the area of ABCD.

Answer 2

Answer:

for plato or gradpoint answer is 4:1 i got it correct :)

Step-by-step explanation: