Question

Evaluate (8^6)(8^-3)(4^-2)/2 A) 8 B) 16 C) 32 D) 64 HELP ME

Answer 1

Answer:

16,A

hope this helps :)

Answer 2

Option (B)  

Answer:

The solution of $\frac{\left(8^{6}\right)\left(8^{-3}\right)\left(4^{-2}\right)}{2} \text { is } 16$

Solution:

Given that

$\frac{8^{6} \times 8^{-3} \times 4^{-2}}{2}$

Rewrite the above expression  

$=\frac{\left(2^{3}\right)^{6} \times\left(2^{3}\right)^{-3} \times\left(2^{2}\right)^{-2}}{2}$

On applying the law of exponent $\left(a^{m}\right)^{n}=a^{m n}$

$=\frac{2^{18} \times 2^{-9} \times 2^{-4}}{2}$

Rewrite the above expression

$=2^{18} \times 2^{-9} \times 2^{-4} \times 2^{-1}$

Again applying the law of exponent $a^{m} \times a^{n}=a^{m+n}$

$=2^{18-9-4-1}$

$=2^{4}$

=16

Value of $\frac{8^{6} \times 8^{-3} \times 4^{-2}}{2} is 16$

Hence option (B) is correct.