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oksano4ka [1.4K]
3 years ago
12

The length of a rectangle is 6cm longer than the width. The perimeter of the rectangle is 92 cm. Find the length of the width of

the rectangle
Mathematics
1 answer:
Vinvika [58]3 years ago
4 0

Answer:

l=26

w=20

Step-by-step explanation:

l-6=w

2l+2w=92

2l+2(l-6)=92

2l+2l-12=92

4l=104

l=26

(26)-6=w

w=20

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vampirchik [111]
1.08 in 9 minutes total
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4 years ago
Read 2 more answers
20 points
irinina [24]

Answer:

(a) 9x^2+16x-4

(b) 9a(2a+5)

(c) (y-6)(y-4)

Step-by-step explanation:

(a)

(9x-2)(x+2)=

9x^2-2x+18x-4=

9x^2+16x-4

(b)

18a^2+45a=

9a(2a+5)

(c)

y^2-10y+24=

(y-6)(y-4)

Hope this helps!

4 0
3 years ago
Solve for x.<br><br> 3x - 13 = 2<br><br> (SHOW YOUR WORK)
Eddi Din [679]

3x-13=2

move -13 to the other side

sign changes from -13 to +13

3x-13+13=2+13

3x=2+13

3x=15

divide both sides by 3 to get x by itself

3x/3=15/3

cross out 3 and 3, divide by 3 and then becomes 1*1*x=x

x=15/3

x=5

answer:

x=5

7 0
3 years ago
Find the equation of a circle with a center at (–7, –1) where a point on the circle is (–4, 3).
gogolik [260]

Answer:

(x + 7)^2 + (y + 1)^2 = 25.

Step-by-step explanation:

The center of a circle is easy to set up. According to the formula below, the formula for the circle will be (x - a)^2 + (y - b)^2 = r^2.

In this case, a = -7 and b = -1, so we have...

(x - (-7))^2 + (y - (-1))^2 = r^2

(x + 7)^2 + (y + 1)^2 = r^2

To get the radius, we need to find the distance between the center and the point on the circle. The distance formula is d = sqrt((x2 - x1)^2 + (y2 - y1)^2).

In this case, x2 = -4, x1 = -7, y2 = 3, and y1 = -1.

sqrt((-4 - -7)^2 + (3 - -1)^2) = sqrt((-4 + 7)^2 + (3 + 1)^2) = sqrt((3)^2 + (4)^2) = sqrt(9 + 16) = sqrt(25) = plus or minus 5.

Since distance can only be positive, the distance is 5 units, meaning that the radius is 5 units.

5^2 = 25

So, your equation should be (x + 7)^2 + (y + 1)^2 = 25.

Hope this helps!

8 0
3 years ago
To the nearest tenth, find the perimeter of ABC with vertices A(-1,4), B(-2,1) and C(2,1). show your work
liubo4ka [24]

we have to firstly apply the distance formula to find the length of sides of the triangle

distance formula = \sqrt{(x_{2} -x_{1})^2 +(y_{2}- y_{1})^2}

So length AB = \sqrt{(-2-(-1))^2+(1-4)^2}= \sqrt{1 +9}=\sqrt{10}

BC= \sqrt{(2-(-2))^2+(1-1)^2}= \sqrt{16+0}=4

AC = \sqrt{(2-(-1))^2+ (1-4)^2}= \sqrt{9+9}=\sqrt{18}=3\sqrt{2}

Now perimeter = AB+BC+AC = \sqrt{10}+4+3\sqrt{2}

Plug in calculator

perimeter= 11.4 units

7 0
3 years ago
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